在#define长度的结构中声明一个数组

问题描述

大家好，

i我正在尝试制作一个结构


#include" globalVars.h"


struct myStruct {

int offset;

unsigned char uChars [numOfGlobalVars -1];


} saveVars，getVars;

我在globalVars.h中有#define numOfGlobalVars ...它没有


main.cpp： 23：错误：''struct myStruct''没有名为''uChars''的成员，

当我稍后在我的代码中尝试访问这些uChars时。


我应该不能这样做吗？


nass

解决方案

它对我有用。告诉我们更多关于您使用的编译器

的版本和内容。


帮派。

它对我有用。告诉我们更多关于你用过的编译器

的版本和内容。


帮派。

Hello everyone,
i am attempting to make a structure

#include "globalVars.h"

struct myStruct{
int offset;
unsigned char uChars[numOfGlobalVars -1];

} saveVars, getVars;
and i have #define numOfGlobalVars in globalVars.h... it does not
compile saying

main.cpp:23: error: ''struct myStruct'' has no member named ''uChars'',
when i try to access these uChars later on in my code.

should i not be able to do that?

nass

解决方案

It works for me. I suggest you post a minimal but complete example.

It worked for me. Tell us a little more about the compiler you''ve used
the version and stuff.

gangs.

It worked for me. Tell us a little more about the compiler you''ve used
the version and stuff.

gangs.

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