使用Rand（）在C ++中获取一个8位数的随机数

问题描述

有人可以向我解释为什么这不起作用，它的编译但不给我结果..阅读除了couts之外的评论，看看它的作用。我真的尝试了一切，没有任何运气。

Could someone please explain to me why this is not working, its compiling but not giving me the results.. read the comments besides the couts to see what its doing. I have literally tried everything and not having any luck whatsoever.

    int i;
    srand (time(NULL));
    i = (rand() % 99999999 + 1);
cout << i << endl; //This cout displays a 5 digit number that counts upwards every time
i = 0;
    while (i < 99999999)
  {
          i = (rand() % 99999999 + 1);
  }
cout << i << endl; //This one stalls my program

推荐答案

long FourDigitRandom()
   {
   return (long) rand() % (9999 + 1);
   }
...
   long l = FourDigitRandom() + (FourDigitRandom() * 10000);
...

int value = (double)rand() / (RAND_MAX + 1) * (range_max - range_min)
            + range_min;

，如下例 []



在您的情况下，range_max = 99999999和range_min = 1.



或者，如果你想确保它总是8位数而没有前导零，那么range_min = 10000000.



问候，

Ian。

as given in the example here rand()[^]

In your case, range_max = 99999999 and range_min = 1.

Or, if you want to ensure it is always 8 digits without leading zeros, then range_min = 10000000.

Regards,
Ian.

int i = 0,j = 0;

i = rand() % 9 + 1;            //First number should not be 0.

for (int k = 1; k < 4; k++) {
    i = i*10 + rand()%10;      //Generate the next 3 digits.
}

for (int k = 0; k < 4; k++) {
    j = j*10 + rand()%10;      //Generate the 4 digits of the lower part.
}

cout<<"Random number : "<<i<<j;

// If you want the 8 digit number, save in long int
long int res = i*1000 + j;
cout<<res;

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