检查该模块是最接近

问题描述

欢迎。我的问题是，我给了，我需要计算平均（这部分我做的）数字数组，但我必须要找到数组元素（模块），这是更接近平均水平。下面贴code（形式main（）的规定）

Welcome. My problem is that I have given an array of numbers which I need to calculate the average (that part I did), but then I have to find the array element (module), which is closer to the average. Below paste the code (a form of main () imposed)

#include <iostream>
using namespace std;


double* aver(double* arr, size_t size, double& average){

    double count;
    for(int p = 0; p < size; p++)
        count += arr[p];
        count /= size;

        double * pointer;
        pointer = &count;
        average = *pointer;
}

int main() {
    double arr[] = {1,2,3,4,5,7};
    size_t size = sizeof(arr)/sizeof(arr[0]);
    double average = 0;
    double* p = aver(arr,size,average);
    cout << p << " " << average << endl;
}

该计划应该给结果

The program should give a result

4 3.66667

4 3.66667

我不知道如何检查哪些元素是最近到另一个，它代入* P

I have no idea how to check which element is nearest to another, and substitute it into *p

我将是任何帮助非常感激。

I will be very grateful for any help.

推荐答案

既然大家都在做的功课的孩子...

Since everybody is doing the kids homework...

#include <iostream>
using namespace std;

double min(double first, double second){
  return first < second ? first : second;
}

double abs(double first){
  return 0 < first ? first : -first;
}


double* aver(double* arr, size_t size, double& average){

    double count;
    for(int p = 0; p < size; p++)
      count += arr[p];

    average = count/size;

    int closest_index = 0;
    for(int p = 0; p < size; p++)
      if( abs(arr[p] - average) <
          abs(arr[closest_index] - average) )
        closest_index = p;

    return &arr[closest_index];
}

int main() {
    double arr[] = {1,2,3,4,5,7};
    size_t size = sizeof(arr)/sizeof(arr[0]);
    double average = 0;
    double* p = aver(arr,size,average);
    cout << *p << " " << average << endl;
    //Above ^^ gives the expected behavior,
    //Without it you'll get nothing but random memory
}

我坚持认为你在p之前需要将*，它给该指针指向太值。无*则该值是存储器位置，这是在这种情况下，不确定的地址。问问你的教授/教师规格是否正确，因为它不是。

I insist that you need the * before the p, it gives the value that the pointer is pointing too. Without the * then the value is the address of the memory location, which is indeterminate in this case. Ask your professor/teacher whether the specification is correct, because it isn't.

尝试和了解所涉及的风格和功能 - 它并不复杂，写这样可以走很长的方式来使你的年级的工作更轻松。

Try and understand the style and functions involved - it isn't complicated, and writing like this can go a long ways to making your graders job easier.

另外该接口是非常漏水的，在实际工作中 - 考虑到一些标准库算法和容器，而不是

Also that interface is a very leaky one, in real work - consider some of the standard library algorithms and containers instead.

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