我怎样才能找到并打印最大值的指数在一个数组？

问题描述

有关我的项目，我需要做一个程序，需要10个号码作为输入，并显示这些数字的模式。该计划应使用两个数组，得花数的数组作为参数，并在阵列返回的max值的方法。

基本上，我到目前为止所做的是使用第二阵列跟踪的多少次出现的数字。纵观初始阵列，你会看到，模式为4（号码出现最多）。在第二阵列，索引4将具有2的值，并且因此2将第二阵列中的最大值。我需要在我的第二个数组来定位这个最大值，并打印索引。我的输出应该是'4'。

我的计划是好的，直到我试图产生'4'，我已经尝试了一些不同的东西，但似乎无法得到它才能正常工作。

感谢您的时间！

 公共类arrayProject {公共静态无效的主要（字串[] args）{
    INT [] arraytwo = {0，1，2，3，4，4，6，7，8，9};
    projecttwo（arraytwo）;
}
公共静态无效projecttwo（INT []数组）{
    / *程序，它接受10个号码作为输入，并显示这些数字的模式。程序应该使用并行
     阵列，得花数的数组作为参数，并在阵列返回的max值的方法* /
    INT modetracker [] =新INT [10];
    INT最大= 0; INT数= 0;
    的for（int i = 0; I＆LT; array.length，我++）{
        modetracker [阵列[我] + = 1; //添加一个modetracker各指标出现的地方数组的元素[I]。
    }    INT索引= 0;
    的for（int i = 1; I＆LT; modetracker.length;我++）{
        INT newnumber = modetracker [I]
        如果（（newnumber＆GT; modetracker [I-1]）== TRUE）{
            指数= I;
        }
    }的System.out.println（+指数）;}
}
 

解决方案

您的错误是在比较 IF（（newnumber＆GT; modetracker [I-1]）你。应检查 newnumber 是更大然后是已经发现的最大也就是说 IF（（newnumber方式＆gt; modetracker [maxIndex]）

您应该改变你的最后行：

  INT maxIndex = 0;
的for（int i = 1; I＆LT; modetracker.length;我++）{
   INT newnumber = modetracker [I]
   如果（（newnumber＆GT; modetracker [maxIndex]））{
   maxIndex = I;
  }
}的System.out.println（maxIndex）;
 

For my project, I need to make a program that takes 10 numbers as input and displays the mode of these numbers. The program should use two arrays and a method that takes array of numbers as parameter and returns max value in array.

Basically, what I've done so far is used a second array to keep track of how many times a number appears. Looking at the initial array, you will see that the mode is 4. (Number that appears most). In the second array, the index 4 will have a value of 2, and thus 2 will be the maximum value in the second array. I need to locate this max value in my second array, and print the index. My output should be '4'.

My program is good up until I attempt to produce the '4', and I've tried a few different things but can't seem to get it to work properly.

Thank you for your time!

public class arrayProject {

public static void main(String[] args) {
    int[] arraytwo = {0, 1, 2, 3, 4, 4, 6, 7, 8, 9};
    projecttwo(arraytwo);
}


public static void projecttwo(int[]array){
    /*Program that takes 10 numbers as input and displays the mode of these numbers. Program should use parallel
     arrays and a method that takes array of numbers as parameter and returns max value in array*/
    int modetracker[] = new int[10];
    int max = 0; int number = 0;
    for (int i = 0; i < array.length; i++){
        modetracker[array[i]] += 1;     //Add one to each index of modetracker where the element of array[i] appears.
    }

    int index = 0;
    for (int i = 1; i < modetracker.length; i++){
        int newnumber = modetracker[i];
        if ((newnumber > modetracker[i-1]) == true){
            index = i;
        }
    } System.out.println(+index);

}
}

解决方案

Your mistake is in comparing if ((newnumber > modetracker[i-1]). You should check if the newnumber is bigger then the already found max. That is if ((newnumber > modetracker[maxIndex])

You should change your last rows to:

int maxIndex = 0;
for (int i = 1; i < modetracker.length; i++){
   int newnumber = modetracker[i];
   if ((newnumber > modetracker[maxIndex])){
   maxIndex = i;
  }
} System.out.println(maxIndex);

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