问题描述
我正在寻找针对此问题的JavaScript实现（适用于IE11）；我的输入是两个这样的数组：
I'm looking for a javascript implementation (for IE11) for this problem; my inputs are two arrays like these:
var array1 = [{id: 1, param:"bon jour"}, {id: 2, param:"Hi"}, {id: 3, param:"Hello"}];
var array2 = [{item: "Peter", values:"1,2", singlevalue:"2"},
{item: "Mark", values:"1,2,3", singlevalue:"3"},
{item: "Lou", values:"2", singlevalue:"2"}];
，然后我应该创建一个包含array2数据和2个新字段（ params和使用array1 [i] .id和array2 [x] .values之间的匹配来评估 param）。并在array1 [i] .id和array2 [x] .singlevalue之间评估 singleparam，结果如下：
and I should create a new array (array3) with array2 data plus 2 new fields ("params" and "singleparam"), using matching between array1[i].id and array2[x].values to evaluate "params" and between array1[i].id and array2[x].singlevalue to evaluate "singleparam", with this kind of result:
array3 = [{item: "Peter", values:"1,2", singlevalue:"2", params:"bon jour,Hi", singleparam:"Hi"},
{item: "Mark", values:"1,2,3", singlevalue:"3", params:"bon jour,Hi,Hello", singleparam:"Hello"},
{item: "Lou", values:"2", singlevalue:"2", params:"Hi", singleparam:"Hi"}];
我是一名JavaScript新手，并且尝试了这种解决方案：
I'm a javascript newbie and I've tried this kind of solution:
var array3 = array2.map(function(x, array1)
{
const newOb = {};
newOb.item = x.item;
newOb.values = x.values;
newOb.singlevalue = x.singlevalue;
newOb.params = function(x.values, array1)
{
var str = "";
var idArray = x.values.split(",");
for(i = 0; i < idArray.lenght; i++)
{
for(j = 0; i < array1.lenght; j++)
{
if(idArray[i] == array1[j].id)
{
str += array1[j].param + ",";
break;
}
}
}
return str;
};
newOb.singleparam = function(x.singlevalue, array1)
{
var val;
for(j = 0; i < array1.lenght; j++)
{
if(array1[j].id == x.singlevalue)
val = array1[j].param;
}
return val;
}
return newOb;
});
console.log(array3);
，出现以下错误：错误：意外的令牌'。'
考虑到array1的元素少于10个，但我想找到一种有效的解决方案，但是array2可以包含1000个以上的对象。
I'd like to find an efficient solution considering that array1 has less than 10 elements, but array2 could contains more than 1000 objects.
在此先感谢您的支持
推荐答案
@Walteann Costa提供的解决方案可以在其他浏览器中显示所需的结果，但不适用于IE浏览器。代码示例使用=> IE浏览器不支持箭头功能。
The solution provided by the @Walteann Costa can show the desired results in other browsers but it will not work for the IE browser as his code sample uses the => Arrow functions that is not supported in the IE browser.
当您的问题询问IE浏览器的解决方案时，我试图修改@Walteann Costa提供的代码示例。下面的修改后的代码可以与IE 11浏览器一起使用。
As your question asks the solution for the IE browser, I tried to modify the code sample provided by the @Walteann Costa. Below modified code can work with the IE 11 browser.
<!doctype html>
<html>
<head>
<script>
"use strict";
var array1 = [{
id: 1,
param: "bon jour"
}, {
id: 2,
param: "Hi"
}, {
id: 3,
param: "Hello"
}];
var array2 = [{
item: "Peter",
values: "1,2",
singlevalue: "2"
}, {
item: "Mark",
values: "1,2,3",
singlevalue: "3"
}, {
item: "Lou",
values: "2",
singlevalue: "2"
}];
function newArray3() {
return array2.map(function (x) {
var newOb = {};
newOb.item = x.item;
newOb.values = x.values;
newOb.singlevalue = x.singlevalue;
newOb.params = paramsFunction(x.values, array1);
newOb.singleparam = singleParamFunction(x.singlevalue, array1);
return newOb;
});
}
function singleParamFunction(x, array1) {
var val,i,j;
for (i = 0; i < array1.length; i++) {
if (array1[i].id.toString() == x) {
val = array1[i].param;
}
}
return val;
}
function paramsFunction(x, array1) {
var str = "";
var idArray = x.split(",");
var i,j;
for (i = 0; i < idArray.length; i++) {
for (j = 0; j < array1.length; j++) {
if (idArray[i] == array1[j].id.toString()) {
str += array1[j].param + ",";
break;
}
}
}
return str;
}
var array3 = newArray3();
console.log(array3[0]);
console.log(array3[1]);
console.log(array3[2]);
</script>
</head>
<body>
</body>
</html>在IE 11中的输出：
Output in the IE 11:
这篇关于Javascript：对象数组映射和与IE11的匹配的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！