如何根据下拉菜单中选择的项目在标签中显示值.

问题描述

所有

我有一个下拉控件(字段名称)和标签(对象名称).我想根据下拉列表中选择的字段名称显示对象名称.
如何使用XML HTTP在标签中显示值.任何人都可以帮助我..在此先感谢.

all

I have a drop down control (Fields Names) and a label (Object Name). I want to display the object name based on the field name selected in the drop down.
How to display the value in the label using XML HTTP. Can any one help me.. thanks in advance.

推荐答案

//---XMLHttpRequest
           var xmlhttp;
           if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari
               xmlhttp = new XMLHttpRequest();
           }
           else {// code for IE6, IE5
               xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
           }
           xmlhttp.onreadystatechange = function () {
               if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
                   var ReturnVal= xmlhttp.responseText;
                   ReturnVal = ReturnVal.replace('',"");
                   ReturnVal=ReturnVal.split("~")[0];
                   document.getElementById("label").value=ReturnVal;

               }
           }
           xmlhttp.open("GET", "http://localhost:1101/aspx/GetObjectName.aspx?FieldsNames=" + FieldsNames+ "&FieldsNamesValue=" + FieldsNamesValue, true);
           xmlhttp.send();

在GetObjectName.aspx页中，根据需要获取相应的值.
即将您的数据集保留在会话中并通过使用select方法获取值；
DataRow [] dr = dataset.Tables [0] .select("condition =" + FieldsNamesValue)

谢谢，
sanjeev

In the GetObjectName.aspx page get the values accordingly as your requirement.
i.e keep your dataset in session and get the values by using select method;
DataRow[] dr=dataset.Tables[0].select("condition="+FieldsNamesValue)

Thanks,
sanjeev

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