修正算术类中的循环依赖

修正算术类中的循环依赖

本文介绍了修正算术类中的循环依赖的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一组类实现奇怪的循环模板模式。然而,诀窍是基类需要返回子类的实例。这里有一个例子:

  template< typename SubType> 
class ArithmeticBase
{
public:
template< typename OtherType>
const加法运算符+(const OtherType& other)
{return Addition(get_subclass(),other);}

// ...
//用于减法,乘法,除法,...

private:
const SubType& get_subclass()const
{return * static_cast< const SubType *> }
};

template< typename OperatorType1,typename OperatorType2>
类加法:ArithmeticBase<加法< OperatorType1,OperatorType2>>
{
public:
添加(const OperatorType1& op1,const OperatorType2& op2)
:op1(op1)
,op2(op2)
{}

private:
const OperatorType1& op1;
const OperatorType2& op2;
};

// ...
//减法,乘法,除法等其他类

编译失败,因为添加类未在 ArithmeticBase class:

  arithmetic.cpp:6:8:error:unknown type name'Addition'
const加法如何解决这个问题?

p>

解决方案

您可以在基类之前转发添加

 模板< typename OperatorType1,typename OperatorType2> 
类加法;
template< typename SubType>
class ArithmeticBase
{
...
};

这允许编译器知道有一个类型添加在定义之前存在。


I have a set of classes implementing the curiously recurring template pattern. However, the trick is that the base class needs to return instances of the subclasses. Here's an example:

template <typename SubType>
class ArithmeticBase
{
public:
    template <typename OtherType>
    const Addition operator+(const OtherType &other)
        {return Addition(get_subclass(), other);}

    // ...
    // Operators for subtraction, multiplication, division, ...

private:
    const SubType &get_subclass() const
        {return *static_cast<const SubType*>(this);}
};

template <typename OperatorType1, typename OperatorType2>
class Addition : ArithmeticBase<Addition<OperatorType1, OperatorType2>>
{
public:
    Addition(const OperatorType1 &op1, const OperatorType2 &op2)
        : op1(op1)
        , op2(op2)
    {}

private:
    const OperatorType1 &op1;
    const OperatorType2 &op2;
};

// ...
// Additional classes for subtraction, multiplication, division, ...

Compiling this fails because the Addition class is not defined before it's used in the ArithmeticBase class:

arithmetic.cpp:6:8: error: unknown type name 'Addition'
        const Addition operator+(const OtherType &other)
              ^

How can I resolve this?

解决方案

You could forward declare Addition before the base class.

template <typename OperatorType1, typename OperatorType2>
class Addition;
template <typename SubType>
class ArithmeticBase
{
...
};

This allows the compiler to know there is a type Addition that exists before it is defined.

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08-13 09:07