本文介绍了如果语句始终为真(字符串)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我这里有一个相当简单的石头,剪刀,剪子程序,在使用if语句时遇到了一些麻烦.由于某些原因,当我输入石头,纸张或剪刀(真值")时,程序始终会执行
I have here a rather simple rock, paper, scissors program where I am having some trouble with if statements. For some reason, when I enter rock, paper, or scissors (True Values), the program always performs
if 'rock' or 'paper' or 'scissors' not in player:
print("That is not how you play rock, paper, scissors!")
由于某种原因.完整的程序如下.
for some reason. The complete program is as below.
computer = ['rock', 'paper', 'scissors']
com_num = randint(0,2)
com_sel = computer[com_num]
player = input('Rock, paper, scissors GO! ')
player = player.lower()
if 'rock' or 'paper' or 'scissors' not in player:
print("That is not how you play rock, paper, scissors!")
if player == 'rock' or 'paper' or 'scissors':
#win
if player == 'rock' and com_sel == 'scissors':
print('You win! ', player.title(), ' beats ', com_sel, '!', sep ='')
if player == "paper" and com_sel == "rock":
print('You win! ', player.title(), ' beats ', com_sel, '!', sep ='')
if player == 'scissors' and com_sel == 'paper':
print('You win! ', player.title(), ' beats ', com_sel, '!', sep ='')
#draw
if player == com_sel:
print('It\'s a draw!')
#lose
if player == 'rock' and com_sel == 'paper':
print('You lose.', com_sel.title(), "beats", player, '!', sep = '')
if player == 'paper' and com_sel == 'scissors':
print('You lose.', com_sel.title(), "beats", player, '!', sep = '')
if player == 'scissors' and com_sel == 'rock':
print('You lose.', com_sel.title(), "beats", player, '!', sep = '')```
推荐答案
if
中的条件错误.
考虑 if
语句并加上括号:
if ('rock') or ('paper') or ('scissors' not in player):
它将始终返回 True
,因为 rock
始终为true.
It will always return True
because rock
will always be true.
您需要交换条件的操作数
You need to swap conditions' operands
if player not in computer:
此交换之后,此行变得无关紧要(并且其条件也是错误的),您需要将其删除:
After this swap, this line becomes irrelevant (and also its conditions are wrong) You need to remove it:
if player == 'rock' or 'paper' or 'scissors':
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