拆分“供应商”使用webpack 2的块

问题描述

我有类似官方 docs
，一切运行完美-我的所有节点模块都位于供应商块中（包括 babel-polyfill）。但是现在，我需要移动babel-polyfill及其所有依赖项来分离块（ polyfills），以便能够在我的供应商捆绑包之前加载它。任何想法如何做到？

I have code splitting config similar to official docsand everything works perfect - all my node modules are in "vendor" chunk (including "babel-polyfill"). But now I need to move babel-polyfill and all it's dependecies to separate chunk ("polyfills") to be able to load it before my vendor bundle. Any ideas how to do that?

我的配置：

...
entry: {
  main: './index.jsx'
},
...
new webpack.optimize.CommonsChunkPlugin({
  name: 'vendor',
  minChunks: function (module) {
    return module.context && module.context.indexOf('node_modules') !== -1;
  }
}),
new webpack.optimize.CommonsChunkPlugin({ name: 'manifest' })
...

推荐答案

获取依赖项

您可以阅读来自 babel-polyfill

const path = require('path');

function getDependencies () {

       // Read dependencies...
       const { dependencies } = require('node_modules/babel-polyfill/package.json');

       // Extract module name
       return Object.keys(dependencies);
}

只需调用它（应该返回带有的数组依赖项）：

Just call it (should return an array with the dependencies):

const dependencies = getDependencies(); // ['module', ...]





检测polyfills

检查模块是否为 babel-polyfill 或依赖项：

 function isPolyfill(module){

     // Get module name from path
     const name = path.posix.basename(module.context)

     // If module has a path
     return name &&

     // If is main module or dependency
     ( name === "babel-polyfill" || dependencies.indexOf(name) !== -1 );
 }

要删除 babel-polyfill 和依赖项只是检查是否返回 false

To remove babel-polyfill and dependencies just check if returns false

new webpack.optimize.CommonsChunkPlugin({
    name: 'vendor',
    minChunks: function (module) {

        // If has path
        return module.context &&

        //If is a node-module
        module.context.indexOf('node_modules')!== -1 &&

        // Remove babel-polyfill and dependencies
        isPolyfill(module) === false;
    }
})

创建polyfills块

仅选择 babel-polyfill 和依赖项仅检查是否返回 true

Create polyfills chunk

To select only babel-polyfill and dependencies just check if returns true

new webpack.optimize.CommonsChunkPlugin({
    name: 'polyfills',

    minChunks: function (module) {

        // If has a path
        return module.context &&

        //If is a node-module
        module.context.indexOf('node_modules')!== -1 &&

        // Select only  babel-polyfill and dependencies
        isPolyfill(module) === true;
    }
})

这篇关于拆分“供应商”使用webpack 2的块的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！