使用Swift类似于SLComposeViewController将Instagram发布到Instagram

问题描述

我有一个iOS Xcode 7 Swift 2项目我正在工作。应用程序将照片发送到 Facebook 和 Twitter 使用：

  var shareToFacebook：SLComposeViewController = SLComposeViewController（forServiceType：SLServiceTypeFacebook）
  

  var shareToTwitter：SLComposeViewController = SLComposeViewController（forServiceType：SLServiceTypeTwitter）
  

爱上这两张社交媒体照片，感觉如何轻松简单。我不需要或想要他们的API。

我想为 Instagram 做类似和简单的事情。没有必要处理 Instagram API 的最佳方法是什么？或者我别无选择？

我的照片数据使用 NSCoding ，而不在 DocumentDirectory 中。我查看了以进行集成，但这是为了保存一张照片在应用程序目录。

只是一些简单的东西，就像我已经拥有的Facebook和Twitter一样。

解决方案

我看了，并找到一个解决方案：

我创建了一个 NSObject ：

  import UIKit 
 import Foundation 
 
 class InstagramManager：NSObject，UIDocumentInteractionControllerDelegate {
 
 private let kInstagramURL =instagram：// app
 private let kUTI =com.instagram.exclusivegram
 private let kfileNameExtension =instagram.igo
 private let kAlertViewTitle =Error
 private let kAlertViewMessage =请安装Instagram应用程序
 
 var documentInteractionController = UIDocumentInteractionController（）
 
 // singleton manager 
 class var sharedManager：InstagramManager {
 struct Singleton {
 static let instance = InstagramManager（）
} 
 return Singleton.instance 
} 
 
 func postImageToInstagramWithCaption（imageInstagram：UIImage，instagramCaption：String，view：UIView）{
 //调用以发布图像标题到instagram应用程序
 
 let instagramURL = NSURL（string：kInstagramURL）
如果UIApplication.sharedApplication（）。canOpenURL（instagramURL！）{
 let jpgPath =（NSTemporaryDirectory（）作为NSString）.stringByAppendingPathComponent（kfileNameExtension）
 UIImageJPEGRepresentation（imageInstagram，1.0）!. writeToFile（jpgPath，atomically：true）
 let rect = CGRectMake（0,0,612,612）
 let fileURL = NSURL。 fileURLWithPath（jpgPath） 
 documentInteractionController.URL = fileURL 
 documentInteractionController.delegate = self 
 documentInteractionController.UTI = kUTI 
 
 //为图像添加标题
 documentInteractionController.annotation = [InstagramCaption：instagramCaption] 
 documentInteractionController.presentOpenInMenuFromRect（rect，inView：view，animated：true）
} else {
 
 //当instagram应用程序不是时显示警报在设备中可用
 UIAlertView（title：kAlertViewTitle，message：kAlertViewMessage，delegate：nil，cancelButtonTitle：Ok）。show（）
} 
} 
 
 
  

然后在我的 @IBAction ：

  let image = self.photoImageView.image 
 InstagramManager.sharedManager.postImageToInstagramWithCaption（image !, instagramCaption：\\ \\（self.description），v iew：self.view）
  

这将打开一个带有开放风格的菜单，用户可以在 Instagram （如果已安装）中打开该应用程序。

I have an iOS Xcode 7 Swift 2 project I'm working on. The app posts photos to Facebook and Twitter using:

var shareToFacebook: SLComposeViewController = SLComposeViewController(forServiceType: SLServiceTypeFacebook)

and

var shareToTwitter: SLComposeViewController = SLComposeViewController(forServiceType: SLServiceTypeTwitter)

Love how easy and simple for just posting a photo to these two social medias. I didn't need or want the APIs for them.

I want to do something similar and simple for Instagram. What is the best way to do this without having to deal with Instagram API? Or do I have no choice?

My photo data is saved using NSCoding, not in the DocumentDirectory. I looked here for integration but this is for a photo saved in the app directory.

Just something simple like what I already have for Facebook and Twitter.

解决方案

I looked here and found a solution:

I created an NSObject:

import UIKit
import Foundation

class InstagramManager: NSObject, UIDocumentInteractionControllerDelegate {

    private let kInstagramURL = "instagram://app"
    private let kUTI = "com.instagram.exclusivegram"
    private let kfileNameExtension = "instagram.igo"
    private let kAlertViewTitle = "Error"
    private let kAlertViewMessage = "Please install the Instagram application"

    var documentInteractionController = UIDocumentInteractionController()

    // singleton manager
    class var sharedManager: InstagramManager {
        struct Singleton {
            static let instance = InstagramManager()
        }
        return Singleton.instance
    }

    func postImageToInstagramWithCaption(imageInstagram: UIImage, instagramCaption: String, view: UIView) {
        // called to post image with caption to the instagram application

        let instagramURL = NSURL(string: kInstagramURL)
        if UIApplication.sharedApplication().canOpenURL(instagramURL!) {
            let jpgPath = (NSTemporaryDirectory() as NSString).stringByAppendingPathComponent(kfileNameExtension)
            UIImageJPEGRepresentation(imageInstagram, 1.0)!.writeToFile(jpgPath, atomically: true)
            let rect = CGRectMake(0,0,612,612)
            let fileURL = NSURL.fileURLWithPath(jpgPath)
            documentInteractionController.URL = fileURL
            documentInteractionController.delegate = self
            documentInteractionController.UTI = kUTI

            // adding caption for the image
            documentInteractionController.annotation = ["InstagramCaption": instagramCaption]
            documentInteractionController.presentOpenInMenuFromRect(rect, inView: view, animated: true)
        } else {

            // alert displayed when the instagram application is not available in the device
            UIAlertView(title: kAlertViewTitle, message: kAlertViewMessage, delegate:nil, cancelButtonTitle:"Ok").show()
        }
    }

}

Then in my @IBAction I used:

let image = self.photoImageView.image
InstagramManager.sharedManager.postImageToInstagramWithCaption(image!, instagramCaption: "\(self.description)", view: self.view)

This opens bring a menu up with the 'open-in' style and the user can open the app in Instagram (if installed).

这篇关于使用Swift类似于SLComposeViewController将Instagram发布到Instagram的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！