问题描述
我已经使用Spring Boot创建了一个基于REST的小型应用程序.该应用程序作为war软件包部署在EAP 6(JBoss)上.由于EAP 6基于Java 1.7，因此我已经在maven pom中将其配置为编译和使用Java 1.7版本.当我部署应用程序时，我可以在服务器日志中看到该控制器正在注册，但是当我点击它时却得到了404.此外，我JBoss并没有选择我的上下文根配置，而是将应用程序名称作为上下文根.我已经测试了所有可能的端点，但是所有东西都给出了404.有人可以建议我一些可以帮助我继续前进的东西吗?
I have created a small REST-based application using spring boot. The application is deployed on EAP 6(JBoss) as a war package.As EAP 6 is based on Java 1.7 I have configured that in my maven pom to compile and use Java 1.7 version.When I am deploying the application I can see in the server logs that the controller is getting registered but when I am hitting it I am getting 404. Also I JBoss is not picking up my context root configuration but taking the application name as the context root. I am tested all the possible endpoints but everything is giving 404.Can someone suggest me something which can help me to proceed forward?
POM文件:
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>1.4.1.RELEASE</version>
<relativePath/> <!-- lookup parent from repository -->
</parent>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<project.reporting.outputEncoding>UTF-8</project.reporting.outputEncoding>
<java.version>1.7</java.version>
</properties>
....
<build>
<plugins>
<plugin>
<artifactId>maven-compiler-plugin</artifactId>
<configuration>
<source>1.7</source>
<target>1.7</target>
</configuration>
</plugin>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
</plugin>
</plugins>
</build>
应用程序配置
package com.org.orderhistory.v2.orderhistory.v2;
import ...
@SpringBootApplication
public class Application extends SpringBootServletInitializer {
@Override
protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
return application.sources(Application.class);
}
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
}
}
package com.org.orderhistory.v2.orderhistory.v2.controllers;
import ...
@RestController
@RequestMapping(value="/myorder/weborders")
public class WebOrderControllers {
@RequestMapping(value="/{webUserId}",method = RequestMethod.GET, produces = "application/json")
public List<WebOrder> getWebOrdersForUser(@PathVariable Long webUserId) {
JBoss日志
2017-10-09 02:24:29,744 [ServerService Thread Pool -- 594] INFO [org.springframework.boot.web.servlet.FilterRegistrationBean] Mapping filter: 'requestContextFilter' to: [/*]
2017-10-09 02:24:30,368 [ServerService Thread Pool -- 594] INFO [org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerAdapter] Looking for @ControllerAdvice: org.springframework.boot.context.embedded.AnnotationConfigEmbeddedWebApplicationContext@5a46b924: startup date [Mon Oct 09 02:24:27 EDT 2017]; root of context hierarchy
2017-10-09 02:24:30,451 [ServerService Thread Pool -- 594] INFO [org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping] Mapped "{[/org/weborders/{webUserId}],methods=[GET],produces=[application/json]}" onto public java.util.List<com.org.www.order.model.WebOrder> com.org.orderhistory.v2.orderhistory.v2.controllers.WebOrderControllers.getWebOrdersForUser(java.lang.Long)
推荐答案
此处完全相同.试试这个:
1.在pom.xml中:
Exact same issue here. Try this:
1. In pom.xml:
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>javax.servlet-api</artifactId>
<scope>provided</scope>
</dependency>
2.添加一个实现WebApplicationInitializer的类:
2. Add a class implements WebApplicationInitializer:
@Configuration
public class WebApplicationInitializerImpl implements WebApplicationInitializer{
@Override
public void onStartup(ServletContext container) throws ServletException {
WebApplicationContext context = getContext();
Dynamic registration = container.addServlet("dispatcher", new DispatcherServlet(context));
registration.setLoadOnStartup(1);
registration.addMapping("/*");
}
private WebApplicationContext getContext() {
AnnotationConfigWebApplicationContext context = new AnnotationConfigWebApplicationContext();
context.setConfigLocation(ApplicationMain.class.getName());
return context;
}
}
3.记住要通过您的应用程序扩展SpringBootServletInitializer:
3. Remember to extend SpringBootServletInitializer by your application:
@SpringBootApplication
public class ApplicationMain extends SpringBootServletInitializer{
@Override
protected SpringApplicationBuilder configure(SpringApplicationBuilder builder) {
return builder.sources(ApplicationMain.class);
}
public static void main(String[] args) {
SpringApplication.run(ApplicationMain.class, args);
}
}
如果有效，则问题与dispatcherServlet有关.
使用Spring boot时，应该已经自动配置了dispatcherServlet. (这是自动配置的一部分)
根据Redhat的解释，这种情况似乎是jboss的问题:
If it works, then the problem is related to dispatcherServlet.
When using Spring boot, a dispatcherServlet should have been configured automatically. (That is a part of auto Configuration)
And this situation seems to be the issue of jboss, according to Redhat's explanation:
要检查您的dispatcherServlet是否按预期注册，请尝试以下操作:
To check if your dispatcherServlet is registered as expected, try this:
[standalone@localhost:9999 /] /deployment=spring-boot-application.war/subsystem=web:read-resource(recursive=true)
不起作用:
{
"outcome" => "success",
"result" => {
"context-root" => "/spring-boot-application",
"servlet" => undefined,
"virtual-host" => "default-host"
}
}
工作:
{
"outcome" => "success",
"result" => {
"context-root" => "/spring-boot-application",
"virtual-host" => "default-host",
"servlet" => {"appServlet" => {
"servlet-class" => "org.springframework.web.servlet.DispatcherServlet",
"servlet-name" => "appServlet"
}}
}
}
希望它可以解决您的问题.
参考:
https://access.redhat.com/solutions/1211203
https://blog.csdn.net/u011160656/article/details/78809239
Hope it solves your problem.
Reference:
https://access.redhat.com/solutions/1211203
https://blog.csdn.net/u011160656/article/details/78809239
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