WPF MenuItem IsChecked绑定不起作用 | IsChecked绑定不起作用

本文介绍了WPF MenuItem IsChecked绑定不起作用的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

有人知道为什么菜单项绑定不起作用吗?

<ToggleButton Name="toggleButton" Checked="checkBoxPublish_Checked" >
    <ToggleButton.Resources>
        <converters:BooleanToHiddenVisibility x:Key="boolToVis"/>
    </ToggleButton.Resources>
    <Grid>
        <Image  Height="auto"  HorizontalAlignment="Left" Margin="5" Name="image1" Stretch="Fill" VerticalAlignment="Top" Width="auto"  />
        <Viewbox >
            <TextBlock Text="Blocked" Opacity="0.7" Foreground="Red"   Visibility="{Binding Path=IsChecked, ElementName=toggleButton, Converter={StaticResource boolToVis}}"/>
        </Viewbox>
    </Grid>
    <ToggleButton.ContextMenu>
        <ContextMenu StaysOpen="True" >
            <MenuItem x:Name="menuItemBlock" Header="Block" Click="menuItemClick"  IsCheckable="True" IsChecked="{Binding ElementName=toggleButton, Path=IsChecked}"/>
            <MenuItem x:Name="menuItemIgnorePtz" Header="Ignore Ptz" Click="menuItemClick"  IsCheckable="True" />
        </ContextMenu>
    </ToggleButton.ContextMenu>
</ToggleButton>

推荐答案

我猜测这是您使用数据绑定时遇到的上下文菜单.

I'm guessing that it is the contextmenu you have problem using data binding with.

切换按钮不在上下文菜单的逻辑树中，因此无法使用ElementName查找切换按钮，请参见 http://blogs.msdn.com/b/mikehillberg/archive/2008/05/23/of- wpf.aspx中的逻辑和可视树

The togglebutton is not in the logical tree of the contextmenu so it can't find the togglebutton using ElementName, see http://blogs.msdn.com/b/mikehillberg/archive/2008/05/23/of-logical-and-visual-trees-in-wpf.aspx

这就是为什么您在VS的输出窗口中收到该绑定错误的原因:

That is why you get an error for that binding in your output window in VS:

要解决此问题，请使用FindAncestor查找切换按钮:

To fix, look up the toggle button using FindAncestor:

<MenuItem
  Header="Block"
  IsCheckable="True"
  IsChecked="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType=ContextMenu}, Path=PlacementTarget.IsChecked}" />

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