有没有办法在 VSCode 中拆分变量?

问题描述

不知道有没有办法在 VSCode 中拆分一些变量?

我的例子会更好地解释我的问题:

我在这样的路径中有一个 exe 文件 C:\path\to\workspace\main\project\project.exe

my cpp 将创建 exe 文件的源路径是这个 C:\path\to\workspace\main\project\test.cpp

我想在 tasks.json 中创建一个 task 但我的变量没有给我正确的路径

如你所知:${workspaceFolder} 是 C:\path\to\workspace

${fileDirname} 返回 C:\path\to\workspace\main\project

和 ${relativeFileDirname}.exe 返回 main\project.exe

和 "${fileDirname}\\${relativeFileDirname}.exe" 的组合作为命令将返回 C:\path\to\workspace\main\project\main\project.exe 那是错误的.

所以我想知道是否还有其他变量只返回当前 file 的 parent 或不返回?

如果 not 可以用 \ 分割变量吗?

我希望它有意义

谢谢

解决方案

请参阅https://github.com/microsoft/vscode/commit/551db7ec94f02a4bdc8999092cf8bef642b3992d>

${fileDirnameBasename} 正在被添加到 vscode v1.52，我相信这就是你正在寻找的.

I wonder there is any way to splitting some variables in VSCode?

my example will explain my question better:

I have an exe file in such path C:\path\to\workspace\main\project\project.exe

my cpp source path that will create exe file is this C:\path\to\workspace\main\project\test.cpp

I want to create a task in tasks.json but my oder of variables does not give me the right path

as you understand:${workspaceFolder} is C:\path\to\workspace

${fileDirname} returns C:\path\to\workspace\main\project

and ${relativeFileDirname}.exe returns main\project.exe

and combination of "${fileDirname}\\${relativeFileDirname}.exe" as a command will return C:\path\to\workspace\main\project\main\project.exe that is wrong.

so I wanted to know there is any other variable that just return the parent of current file or not?

if not can we split variables with \ ?

I hope it makes some sense

thanks

解决方案

see https://github.com/microsoft/vscode/commit/551db7ec94f02a4bdc8999092cf8bef642b3992d

${fileDirnameBasename} is being added to vscode v1.52 which I believe is what you are looking for.

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