导航到目的地时仅创建一个片段实例(android)

问题描述

我正在使用导航组件.导航时我不想创建新的片段实例，如果它已经存在于 backstack 中并弹出前面已经存在的片段.

I am using Navigation component. when navigating I want to not create new instance of fragment if it already exists in backstack and pop that already existing in front.

    findNavController().navigate(RequestTransferFragmentDirections.actionRequestTransferFragmentToBlankFragment())

寻找解决方案.

谢谢.

推荐答案

我遇到了同样的问题，但不幸的是，以前的解决方案对我不起作用，尽管它们应该解决问题.谢谢顺便说一句！:)

I faced the same problem, but the previous solutions didn't work for me unfortunately, in spite of they are supposed to fix the issue. Thanks btw! :)

这对我有用，适合您的代码是:

This worked for me, adapted to your code would be:

findNavController().navigate(
    RequestTransferFragmentDirections.actionRequestTransferFragmentToBlankFragment()),
    NavOptions.Builder().setLaunchSingleTop(true).build()
)

我在navigate() 文档，我们可以通过 options，因此通过传递 NavOptions.Builder().setLaunchSingleTop(true).build() 将创建此类片段的单个实例.

I saw in the navigate() documentation that we can pass options, so by passing NavOptions.Builder().setLaunchSingleTop(true).build() will create a single instance of such fragment.

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