非原始类型GraphTraversal上创建ValueField

非原始类型GraphTraversal上创建ValueField

本文介绍了Gremlin for CosmosDB-无法在非原始类型GraphTraversal上创建ValueField的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试执行查询,但遇到此错误.下面的查询是我要实现的最简单的形式.

I'm trying to execute a query but facing this error. Below query is the simplest form of what I was trying to achieve.

g.V('Users12345').as('u').
  project('id', 'email', 'test').
    by('id').
    by('emailId').
    by(where(values('id').is(eq(select('u').values('id')))))

我试图在项目内部使用select.我在这里想念什么?

I was trying to use select inside project. What's that I'm missing here?

推荐答案

无效部分是 eq(select('u').values('id')).我猜最简单形式的查询"意味着您意识到它毫无意义.假设 u 实际上不是所投影的用户,则您可能想做更多类似的事情:

The invalid part is eq(select('u').values('id')). I guess "the query in its simplest form" means that you're aware of it being pointless. Assuming that u is actually not the same user that's being projected, you probably want to do something more like this:

g.V('Users12345').as('u').
  project('id', 'email', 'test').
    by('id').
    by('emailId').
    by(coalesce(where(eq('u')).by('id').constant(true), constant(false)))

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08-12 18:36