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问题描述

我想创建自定义存储库:

I wanted to create custom repository :

public interface FriendRepositoryCustom {

    Page<Friend> findFriends(FriendCriteria friendCriteria, Pageable pageable);
}

及其实现:

@Repository
@Transactional(readOnly = true)
public class FriendRepositoryCustomImpl implements FriendRepositoryCustom {

    @PersistenceContext
    EntityManager entityManager;

    @Override
    public Page<Friend> findFriends(FriendCriteria friendCriteria, Pageable pageable) {
    ...
    }

并将其添加到主存储库:

And added it to main repository :

@Repository
public interface FriendRepository extends JpaRepository<Friend, Long>, JpaSpecificationExecutor<Friend>, FriendRepositoryCustom {

}

启动应用程序时出现此错误:

When i start application i get this error :

推荐答案

您可能将自己的实现类命名为错误.

You are probably naming your implementation class wrong.

请注意,命名期望随着Spring Data 2.0的改变而改变.

Note that the naming expectations changed with Spring Data 2.0.

对于< 2.0必须将实现命名为带有附加Impl后缀的最终存储库接口. 请参阅匹配参考文档的示例.

For < 2.0 the implementation had to be named as the final repository interface with an additional Impl suffix. See the matching reference documentation for an example.

对于> = 2.0,必须将实现命名为带有附加Impl后缀的自定义接口. 请参阅当前参考文档中的示例.

For >= 2.0 the implementation has to be named as the custom interface with an additional Impl suffix. See the current reference documentation for an example.

注意:您不需要任何@Repository批注.

Note: You don't need any of the @Repository annotations.

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08-12 17:57