在Python中将两个列表连接到元组

问题描述

我想在python中使用join函数(不是任何其他函数)将两个列表合并到嵌套列表中，假设列表的长度相等，例如:

I want to use the join function in python (not any other function) to merge two lists into nested lists, assuming the lists are of equal length, for example:

list1 = [1, 2, 3]

list2 = ["a", "b", "c"]

我希望它生成这样的新列表:

I want it to produce a new list like this:

[[1,"a"], [2,"b"], [3,"c"]]

推荐答案

我认为您不理解str.join的用途.

I don't think you understand what str.join is for.

str.join 是采用可迭代的字符串(通常是列表)，并返回一个新的字符串对象，该对象是由调用方法的字符串分隔的那些字符串的串联.

str.join is a string method that takes an iterable (usually a list) of strings and returns a new string object that is a concatenation of those strings separated by the string that the method was invoked on.

下面是一个演示:

>>> strs = ['a', 'b', 'c']
>>> ''.join(strs)
'abc'
>>> '--'.join(strs)
'a--b--c'
>>>

这意味着您不会将str.join用于尝试执行的操作.相反，您可以使用 zip 和列表理解:

This means that you would not use str.join for what you are trying to do. Instead, you can use zip and a list comprehension:

>>> list1 = [1, 2, 3]
>>> list2 = ["a", "b", "c"]
>>> [list(x) for x in zip(list1, list2)]
[[1, 'a'], [2, 'b'], [3, 'c']]
>>>

但是请注意，如果您使用的是Python 2.x，则可能要使用 itertools.izip 而不是zip:

Note however that, if you are on Python 2.x, you may want to use itertools.izip instead of zip:

>>> from itertools import izip
>>> list1 = [1, 2, 3]
>>> list2 = ["a", "b", "c"]
>>> [list(x) for x in izip(list1, list2)]
[[1, 'a'], [2, 'b'], [3, 'c']]
>>>

就像Python 3.x zip一样，itertools.izip将返回迭代器(而不是像Python 2.x zip这样的列表).这样可以提高效率，尤其是在处理较大的列表时.

Like the Python 3.x zip, itertools.izip will return an iterator (instead of a list like the Python 2.x zip). This makes it more efficient, especially when dealing with larger lists.

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