C:多个 scanf，当我输入一个 scanf 的值时，它会跳过第二个 scanf

问题描述

我有这个代码块(函数被省略，因为逻辑是家庭作业的一部分):

I have this block of code (functions omitted as the logic is part of a homework assignment):

#include <stdio.h>

int main()
{
    char c = 'q';
    int size;

    printf("
Shape (l/s/t):");
    scanf("%c",&c);

    printf("Length:");
    scanf("%d",&size);

    while(c!='q')
    {
        switch(c)
        {
            case 'l': line(size); break;
            case 's': square(size); break;
            case 't': triangle(size); break;
        }


        printf("
Shape (l/s/t):");
        scanf("%c",&c);

        printf("
Length:");
        scanf("%d",&size);
    }

    return 0;
}

前两个 Scanf 工作得很好，一旦我们进入 while 循环就没问题了，我有一个问题，当你应该被提示输入一个新的形状字符时，​​它反而跳到 printf of Length 并等待从那里获取字符的输入，然后在循环的下一次迭代中输入小数.

The first two Scanf's work great, no problem once we get into the while loop, I have a problem where, when you are supposed to be prompted to enter a new shape char, it instead jumps down to the printf of Length and waits to take input from there for a char, then later a decimal on the next iteration of the loop.

预循环迭代:

Scanf:形状.效果很好
Scanf:长度.没问题

Scanf: Shape. Works Great
Scanf: Length. No Problem

循环 1.

Scanf:形状.跳过这个
Scanf:长度.问题，这个 scanf 映射到形状字符.

Scanf: Shape. Skips over this
Scanf: length. Problem, this scanf maps to the shape char.

循环2
Scanf:形状.跳过这个
Scanf:长度.问题，这个 scanf 现在映射到大小 int.

Loop 2
Scanf: Shape. Skips over this
Scanf: length. Problem, this scanf maps to the size int now.

为什么要这样做?

推荐答案

scanf("%c") 从 键读取换行符.

scanf("%c") reads the newline character from the key.

当你输入 15 时，你输入一个 1，一个 5，然后按 钥匙.所以现在输入缓冲区中有三个字符.scanf("%d") 读取 1 和 5，将它们解释为数字 15，但是换行符仍在输入缓冲区中.scanf("%c") 会立即读取这个换行符，然后程序会继续下一个 scanf("%d")，并等待你输入一个数字.

When you type let's say 15, you type a 1, a 5 and then press the key. So there are now three characters in the input buffer. scanf("%d") reads the 1 and the 5, interpreting them as the number 15, but the newline character is still in the input buffer. The scanf("%c") will immediately read this newline character, and the program will then go on to the next scanf("%d"), and wait for you to enter a number.

通常的建议是使用 fgets 读取整行输入，并在单独的步骤中解释每一行的内容.解决您当前问题的一个更简单的方法是在每个 scanf("%d") 之后添加一个 getchar().

The usual advice is to read entire lines of input with fgets, and interpret the content of each line in a separate step. A simpler solution to your immediate problem is to add a getchar() after each scanf("%d").

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