问题描述
我在Vue中有一个看起来像这样的数据对象
I have a data object in vue that looks like this
rows[
0 {
title: "my title",
post: "my post text",
public: false,
info: "some info"
},
1 {
title: "my title",
post: "my post text"
public: true,
info: "some info"
},
2 {
title: "my title",
post: "my post text"
public: false,
info: "some info"
}
]
然后我复制该对象并根据需要删除某些属性,然后再将该对象发布到我的后端,如下所示:
I then copy that object and remove certain properties if needed before posting the object to my backend like this:
var postData = this.rows;
postData.forEach(function(o) {
if (o.public === true) {
delete o.info;
}
});
var uploadData = {};
uploadData.blogpost = postData;
axios({
method: 'post',
url: myUrl,
responseType: 'json',
data: uploadData
})
问题是delete o.info;
还将从我的 vm 根数据中删除该属性,而且我不知道为什么,因为我创建了一个新的变量/将根数据复制到了该变量中.那么,如何在发布数据之前从数据中删除某些对象属性而又不更改vue中的根数据 vm ?
The problem is that delete o.info;
will also remove the property from my vm root data, and I dont understand why since I created a new varible/copied the root data into that one. So how can I remove certain object properties from my data before posting it without altering my root data vm in vue ?
推荐答案
您需要通过克隆获取数据的副本.有多种克隆数据的方法,我建议使用lodash函数cloneDeep
You need to take a copy of your data by cloning it. There are various ways of cloning the data, I would recommend using lodash's function, cloneDeep
postDataCopy = _.cloneDeep(postData)
postDataCopy = _.cloneDeep(postData)
然后,您可以根据需要修改postDataCopy
,而无需修改原始文件.
Then you can modify postDataCopy
as you like without modifying the original.
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