问题描述
我需要基于unicode字符串构建一个re模式（例如，我有 word，并且我需要类似^ word | word的内容）。但是，单词可以包含特殊的re字符。要按原样匹配单词，我需要在unicode字符串中转义特殊的re字符。基本的re.escape（）函数可完成ascii字符串的工作。
I need to build an re pattern based on the unicode string (e.g. I have "word", and I need something like ^"word"| "word"). However the "word" can contain special re characters. To match the "word" as it is, I need to escape special re characters in unicode string. The basic re.escape() function does the job for ascii strings. How can I do this for unicode?
推荐答案
re.escape（）在每个不是ASCII字母数字的字符之前插入反斜杠。实际上，这实际上可能会导致插入许多不必要的反斜杠，但是，Python会忽略不会启动公认的转义序列的反斜杠，因此不会造成很大的危害（可能会降低性能）。
re.escape() inserts a backslash before every character that's not an ASCII alphanumeric. This may in fact lead to a multitude of unnecessary backslashes to be inserted, however, Python ignores backslashes that don't start a recognized escape sequence, so there is no big harm done (except possibly some performance penalty).
但是如果您想构建更严格的 escape（），则可以：
But if you want to build a stricter escape(), you can:
def escape(s):
return re.sub(r"[(){}\[\].*?|^$\\+-]", r"\\\g<0>", s)
仅涉及实际的正则表达式元字符。我当然希望我不会错过任何一个：）
which only touches the actual regex metacharacters. I sure hope I didn't miss any :)
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