问题描述
目前，我的代码适用于包含一组括号的输入。
So currently, my code works for inputs that contain one set of parentheses.
var re = /^.*\((.*\)).*$/;
var inPar = userIn.replace(re, '$1');
...意味着当用户输入化学式Cu（NO3）2时，警告inPar返回NO3 ），我想要的。
...meaning when the user enters the chemical formula Cu(NO3)2, alerting inPar returns NO3) , which I want.
但是，如果输入Cu（NO3）2（CO2）3，则仅返回CO2。
However, if Cu(NO3)2(CO2)3 is the input, only CO2) is being returned.
我在RegEx中不太了解，所以为什么会发生这种情况，有没有办法在发现它们后将NO3和CO2）放入数组？
I'm not too knowledgable in RegEx, so why is this happening, and is there a way I could put NO3) and CO2) into an array after they are found?
推荐答案
您想使用而不是String.replace。您还希望正则表达式匹配括号中的多个字符串，因此您不能拥有^（字符串的开头）和$（字符串的结尾）。在括号内匹配时我们不能贪婪，所以我们将使用。*？
You want to use String.match instead of String.replace. You'll also want your regex to match multiple strings in parentheses, so you can't have ^ (start of string) and $ (end of string). And we can't be greedy when matching inside the parentheses, so we'll use .*?
逐步完成更改后，我们得到：
Stepping through the changes, we get:
// Use Match
"Cu(NO3)2(CO2)3".match(/^.*\((.*\)).*$/);
["Cu(NO3)2(CO2)3", "CO2)"]
// Lets stop including the ) in our match
"Cu(NO3)2(CO2)3".match(/^.*\((.*)\).*$/);
["Cu(NO3)2(CO2)3", "CO2"]
// Instead of matching the entire string, lets search for just what we want
"Cu(NO3)2(CO2)3".match(/\((.*)\)/);
["(NO3)2(CO2)", "NO3)2(CO2"]
// Oops, we're being a bit too greedy, and capturing everything in a single match
"Cu(NO3)2(CO2)3".match(/\((.*?)\)/);
["(NO3)", "NO3"]
// Looks like we're only searching for a single result. Lets add the Global flag
"Cu(NO3)2(CO2)3".match(/\((.*?)\)/g);
["(NO3)", "(CO2)"]
// Global captures the entire match, and ignore our capture groups, so lets remove them
"Cu(NO3)2(CO2)3".match(/\(.*?\)/g);
["(NO3)", "(CO2)"]
// Now to remove the parentheses. We can use Array.prototype.map for that!
var elements = "Cu(NO3)2(CO2)3".match(/\(.*?\)/g);
elements = elements.map(function(match) { return match.slice(1, -1); })
["NO3", "CO2"]
// And if you want the closing parenthesis as Fabrício Matté mentioned
var elements = "Cu(NO3)2(CO2)3".match(/\(.*?\)/g);
elements = elements.map(function(match) { return match.substr(1); })
["NO3)", "CO2)"]
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