使用常量修饰符引用

使用常量修饰符引用

本文介绍了使用常量修饰符引用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

double&val = 66.6; //非法

const double&val = 66.6; // legal

我刚刚做了一些演示程序,并通过上述概念,但无法确定上述概念的确切需求。 const在第二种情况下究竟做了什么魔术?

有谁可以让我知道我们在实时编程中可以使用这个概念到底在哪里?

double &val = 66.6; //illegal
const double &val = 66.6; //legal
I was just doing some demo programs and came through the above concept but not able to identify what exactly the need of the above concept . what magic exactly const is doing in the second case ?
can anyone please let me know where exactly we can use this concept in real time programming ?

推荐答案

Quote:

const double& val = 66.6; // legal

const double &val = 66.6; //legal

您只能将常量用作 rvalue ,因此不需要 val 引用一个实际地址(即编译器可以用常量 66.6 隐式替换每次出现的val。)



注意你不能将相同的参数应用于

You may use a constant only as rvalue hence there is no need for val to refer to an actual address (that is the compiler may implicitly substitute every occurrence of val with the constant 66.6).

Note you cannot apply the same argument to the

Quote:

double& val = 66.6; //非法

double &val = 66.6; //illegal

行。


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08-12 05:53