Java - 不可稀疏的日期，需要格式匹配“GMT-0400”

问题描述

我有以下Java：

DateFormat formatter = new SimpleDateFormat(
    "EEE MMM dd yyyy HH:mm:ss zZ (zzzz)", Locale.ENGLISH);
Calendar cal = Calendar.getInstance();
cal.set(2011, Calendar.APRIL, 1);
out.println(formatter.format(cal.getTime()));
out.println();

Date date;
try {
    date = formatter
        .parse("Fri Apr 01 2011 00:00:00 GMT-0400 (Eastern Daylight Time)");
} catch (ParseException e) {
    out.println("Failed to parse date: " + e.getMessage());
    e.printStackTrace(out);
}

这是一个servlet，而 / code> -constructed date显示为：

This is in a servlet, and the Calendar-constructed date comes out as:

这个外观与日期字符串的格式一样，除了 EDT-0400 与所需的 GMT-0400 。当尝试解析日期字符串时，代码将失败：

This looks like the same format as the date string I'm trying to parse, except for EDT-0400 versus the desired GMT-0400. The code fails when trying to parse the date string:

如何解析这样一个字符串？这是来自Sencha Touch 1.1.1模型中的JavaScript日期，存储在WebSQL本地存储中。

How can I parse such a string? This is coming from a JavaScript date in a Sencha Touch 1.1.1 model, stored in WebSQL local storage.

推荐答案

由于某些原因GMT-0400不工作，UTC-0400正在工作。您可以用UTC替换GMT。

For some reason GMT-0400 isnt' working, and UTC-0400 is working. You can replace GMT with UTC.

请注意，这部分将被完全忽略 - 时区将从括号中找到（至少在我的机器上，JDK 6）

Note that this part will be completely ignored - the timezone will be resolved from what's found in the brackets (at least on my machine, JDK 6)

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