问题描述
设计一个等价于以下语句的逻辑表达式:
x 是三个或五个元素的列表，其中的第二个元素是字符串 'Hip' 并且第一个不是数字或布尔值.
x is a list of three or five elements, the second element of which is the string 'Hip' and the first of which is not a number or Boolean.
我有什么:
x = ['Head', 'Hip', 10]
print x[1] is 'Hip'
我的问题:你如何检查它是布尔值还是数字?
My question: How do you check for whether or not it is a Boolean or a number?
推荐答案
回答具体问题:
isinstance(x[0], (int, float))
这将检查 x[0] 是否是元组 (int, float) 中任何类型的实例.
This checks if x[0] is an instance of any of the types in the tuple (int, float).
您也可以在其中添加 bool，但这不是必需的，因为 bool 本身就是 int 的子类.
You can add bool in there, too, but it's not necessary, because bool is itself a subclass of int.
文档参考:
要评论您当前的代码，您不应该依赖短字符串的实习.您应该使用 == 运算符比较字符串:
To comment on your current code, you shouldn't rely on interning of short strings. You are supposed to compare strings with the == operator:
x[1] == 'Hip'
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