本文介绍了多个Ajax请求烧成后回调完成的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

loadInfo: function(){
    var jsonCounter = 0,
    room = ['room1','room2','room3'],
    dates = [],
    prices = []

    $.each(booking.rooms, function(key, room_name) {
        $.getJSON('/get_info.php?room='+room_name, function(data) {
            dates[room_name] = data
            jsonCounter++
        })
        $.getJSON('/get_info.php?room='+room_name+'&prices', function(data) {
            prices[room_name] = data
            jsonCounter++
        })

    })

    function checkIfReady() {
        if (jsonCounter === rooms.length * 2) {
            clearInterval(timer)
            run_the_rest_of_the_app()
        }
    }

    var timer = setInterval(checkIfReady, 100)

}

(修改了很多,因为它是一类等等等等的一部分。)

(Modified a lot, as it's part of a class etc etc.)

目前,这感觉有点hackish,作为定时器的使用似乎垃圾。我会用$。当和$ .done,但我不知道有多少间可能有,所以我不知道该怎么投入的时候。

At the moment this feels a bit hackish, as the timer usage seems rubbish. I would use $.when and $.done, but I don't know how many rooms there might be, so I don't know what to put into when.

如何在AJAX请求我保证run_the_rest_of_the_app()仅被调用一次全部回来了?

How do I ensure that run_the_rest_of_the_app() only gets called once all of the AJAX requests come back?

推荐答案

  • VAR activeAJAX = 0;

在做一个AJAX调用 activeAJAX ++;

Before making an AJAX call, activeAJAX++;

在完成一个AJAX调用(回调)后:如果(--activeAJAX == 0){allDone(); }

After completing an AJAX call (in the callback): if (--activeAJAX == 0) { allDone(); }

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08-12 04:45