Junit for JiraRestClient创建问题

问题描述

我正在尝试为以下方法编写JUnit测试，这会产生一个新的Jira问题，是否有人知道如何模拟JiraRestClient或是否有其他方法为此编写测试

I am trying to write a JUnit test for following method which creates a new Jira issue, do anyone know how to mock JiraRestClient or is there any other way to write a test for this

我的代码是

public Issue createNewIssue(BasicProject project, BasicUser assignee, BasicIssueType issueType, String summary, String description, String parentKey, File attachment)
 {
    try
    {
      IssueInputBuilder issueBuilder = new IssueInputBuilder(project, issueType);
      issueBuilder.setDescription(description);
      issueBuilder.setSummary(summary);
      issueBuilder.setProjectKey(project.getKey());
      issueBuilder.setIssueType(issueType);
      issueBuilder.setAssignee(assignee);
      if(parentKey != null)
      {
        Map<String, Object> parent = new HashMap<String, Object>();
        parent.put("key", parentKey);
        FieldInput parentField = new FieldInput("parent", new ComplexIssueInputFieldValue(parent));
        issueBuilder.setFieldInput(parentField);
      }
      IssueInput issueInput  = issueBuilder.build();

      IssueRestClient issueClient = getJiraRestClient().getIssueClient();
      BasicIssue newBasicIssue = issueClient.createIssue(issueInput, pm);
      Issue newIssue = issueClient.getIssue(newBasicIssue.getKey(), pm);
      if(attachment != null && newIssue != null)
        issueClient.addAttachments(pm, newIssue.getAttachmentsUri(), attachment);
      return newIssue;
    }
    catch (RestClientException e)
    {
      LOGGER.debug("Error while creating new Jira issue for input paramenters project : " + (project != null ? project.getName() : null) + " assignee : " +(assignee != null ? assignee.getName() : null)
          + " issueType : " + (issueType != null ? issueType.getName() : null) + " summary : " + summary + " description : " + description);
      return null;
    }
  }

更新

我想到的一件事是传递一个参数，该参数将确定方法是否正在测试中运行，但是这会干扰我不想要的API.但是要编写测试，我必须逃脱呼叫

One thing I am thinking of is to pass one parameter which will decide if method is running from test but then it will disturb the API which I don't want. But to write a test I must need to escape the call

BasicIssue newBasicIssue = issueClient.createIssue(issueInput, pm);

该怎么做?

推荐答案

确定.由于我没有直接使用JIRA Open API.相反，我使用了 JIRA客户端来自动执行与JIRA相关的任务.

OK. Since I've not used JIRA Open APIs directly. Instead I've used JIRA Client to automate JIRA related tasks.

为了编写JIRA的单元测试，您需要在实现JIRA通用方法的地方模拟函数.例如，如果您希望获得特定缺陷/故障单的附件列表，则您的方法应类似于:

In order to write unit tests for JIRA, you need to mock functions where you have implemented JIRA generic methods. For example, if you wish to get a list of attachments to a particular defect / ticket, your method would look like:

public class Generics {

private JiraClient jira;

    @Step("Get added attchments against issue <issueId>")
    public List<Attachment> getAttachments(String issueId) {
        List<Attachment> listOfAttachments = null;
        try {
            Issue issue = jira.getIssue(issueId);
            listOfAttachments = issue.getAttachments();
            LOGGER.info("Current Attachments to " + issueId + " " + listOfAttachments);
        } catch (Exception ex) {
            ex.printStackTrace();
        }
        return listOfAttachments;
    }
}

等效的JUnit测试:

Equivalent JUnit test:

public class JiraUnitTests {

    @Mock
    List<Attachment> attachments;

    @Test
    public void testGetAttachment() {
        Generics generics = Mockito.mock(Generics.class);
        Mockito.when(generics.getAttachments(Matchers.any(String.class))).thenReturn(attachments);
        Assert.assertEquals(attachments, generics.getAttachments(Matchers.any(String.class)));
    }

我嘲笑了泛型类的以下数据成员:

I have mocked below data members from Generics class:

1. 各种附件
   
2. 方法getAttachments()

在这里，您实际上并不需要模拟JIRA Client.相反，您可以模拟方法(如果您尚未修改核心业务逻辑/该方法的目的)

Here, You don't really need to mock JIRA Client. Instead you could mock methods (if you have not modified core business logic / purpose of that method)

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