本文介绍了如何在MATLAB中调整矩阵的大小?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

假设我有一个 1×12 矩阵,我想将其大小调整为 4×3 矩阵.我该怎么办?

Suppose I had a 1-by-12 matrix and I wanted to resize it to a 4-by-3 matrix. How could I do this?

我当前的解决方案有点难看:

My current solution is kind of ugly:

for n = 1:(length(mat)/3)
    out(n,1:3) = mat( ((n-1)*3 + 1):((n-1)*3 + 3) );
end

有更好的方法吗?

推荐答案

reshape当然是正确的解决方案,如 @gnovice .

reshape is of course the proper solution, as stated by @gnovice.

reshape的一个不错的功能是它允许这样做:

A nice feature of reshape is that it allows this:

A = 1:12;
B = reshape(A,4,[]);
B =
     1     5     9
     2     6    10
     3     7    11
     4     8    12

因此,如果您不知道会有多少列,reshape将为您计算出来.同样,如果您将其省略,则reshape将填写行数.

So if you don't know how many columns there will be, reshape will compute it for you. Likewise, reshape will fill in the number of rows, if you leave that out.

C = reshape(A,[],4)
C =
     1     4     7    10
     2     5     8    11
     3     6     9    12

这篇关于如何在MATLAB中调整矩阵的大小?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-31 09:15