本文介绍了如何在MATLAB中调整矩阵的大小?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
假设我有一个 1×12 矩阵,我想将其大小调整为 4×3 矩阵.我该怎么办?
Suppose I had a 1-by-12 matrix and I wanted to resize it to a 4-by-3 matrix. How could I do this?
我当前的解决方案有点难看:
My current solution is kind of ugly:
for n = 1:(length(mat)/3)
out(n,1:3) = mat( ((n-1)*3 + 1):((n-1)*3 + 3) );
end
有更好的方法吗?
推荐答案
reshape
当然是正确的解决方案,如 @gnovice .
reshape
is of course the proper solution, as stated by @gnovice.
reshape
的一个不错的功能是它允许这样做:
A nice feature of reshape
is that it allows this:
A = 1:12;
B = reshape(A,4,[]);
B =
1 5 9
2 6 10
3 7 11
4 8 12
因此,如果您不知道会有多少列,reshape
将为您计算出来.同样,如果您将其省略,则reshape
将填写行数.
So if you don't know how many columns there will be, reshape
will compute it for you. Likewise, reshape
will fill in the number of rows, if you leave that out.
C = reshape(A,[],4)
C =
1 4 7 10
2 5 8 11
3 6 9 12
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