Yii模型阵列? | Yii模型阵列

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问题描述

如何将 Trips::model()->findAll() 的结果转换为数组?

How can I convert the result of Trips::model()->findAll() to an array?

推荐答案

我在这里假设您只需要检索裸数组，而不需要检索任何关联的模型对象.

I'm going on the assumption here that you only need to retrieve just the bare arrays, and not any associated model objects.

这样做:

$model = Trips::model();
$trips = $model->getCommandBuilder()
               ->createFindCommand($model->tableSchema, $model->dbCriteria)
               ->queryAll();

这类似于 Yii::app()->db->createCommand('SELECT * FROM tbl')->queryAll(); 示例，除了:

This is like the Yii::app()->db->createCommand('SELECT * FROM tbl')->queryAll(); examples, except:

它会向模型询问表名；您无需在模型和查询中都写入表名.

It'll ask the model for the table name; you won't need to write the table name in both the model and the query.

你可以在范围函数>$model 首先，例如
$model = Trips::model()->short()->destination('Austin, TX');
这样做意味着您可以使用模型现有的查询快捷方式，而不是直接将它们放入查询中.

You can call scoping functions on $model first, eg.
$model = Trips::model()->short()->destination('Austin, TX');
Doing this means you can use the model's existing query shortcuts, instead of putting them in the query directly.

相比之下，$trips = Trips::model()->findAll();(使用 foreach)有点浪费，因为您从数据库中提取行，设置一堆对象，然后将它们全部扔掉.它适用于小型结果集，但如果您正在查看一长串旅行，我不会使用它.

In contrast, the $trips = Trips::model()->findAll(); (using foreach) is a bit wasteful, in that you're pulling the rows from the database, setting up a bunch of objects, and then throwing them all away. It'll work fine for small result sets, but I wouldn't use that if you're looking at a long list of Trips.

警告:
不过，如果这只是一个快速原型，请务必使用 createCommand() 或 findAll()-and-loop 示例.

Caveat:
If this is just a quick prototype, though, by all means use the createCommand() or findAll()-and-loop examples.

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