问题描述
我需要检查文件是否本地打开（同一台机器或网络）。我正在使用：
I need to check if a file is opened "locally" (same machine or network). I'm using:
<?php
if ((substr($_SERVER['REMOTE_ADDR'],0,8) == "192.168.") || ($_SERVER['REMOTE_ADDR'] == "127.0.0.1")) {
// client is local
} else {
// client is not local
}
但我不确定这是不是最好的办法。
But I'm not sure this is the best way.
这样做有什么更加万无一失的方法？
What is a more foolproof way of doing this?
推荐答案
万无一失，一如既往，可能会非常棘手。
"Foolproof," as always, can be tricky.
如果我们将自己局限于IPv4，那么检查127.0.0.1会处理localhost情况，但是检查192.168。是完全错误的 - 只有在使用16位子网掩码的192.168网络上的服务器上运行脚本时，它才有效。
If we do restrict ourselves to IPv4, then checking for "127.0.0.1" takes care of the localhost case, but checking against "192.168." is plain wrong - it will only work if the script is being run on a server which happens to be on the 192.168 network, using a 16-bit subnet mask.
检查对$ _SERVER ['SERVER_ADDR']的$ _SERVER ['REMOTE_ADDR']将是一个更好的选择。但是，这仍然没有考虑多宿主主机（即除了127.0.0.1之外还有几个IP地址的主机）的情况。
Checking $_SERVER['REMOTE_ADDR'] against $_SERVER['SERVER_ADDR'] would be a better bet. This still doesn't take care of the case of a multi-homed host (ie one which has several IP addresses in addition to 127.0.0.1), though.
In为了捕获所有相同的网络情况，您需要检查SERVER_ADDR和子网掩码的组合对REMOTE_ADDR，但子网掩码在$ _SERVER中不可用。
In order to catch all same-network cases, you'd need to check the combination of SERVER_ADDR and subnet mask against REMOTE_ADDR, but the subnet mask isn't available in $_SERVER.
但我发现了一个功能，可以完成您想要的功能。这是几个屏幕，它叫做clientInSameSubnet。不是我的代码，但看起来是正确的。
BUT I found a function which does pretty much what you want here. It's a couple of screens down and it's called clientInSameSubnet. Not my code, but looks right.
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