Django-解析JSONP(带有填充的Json)

问题描述

我正在使用 JSONP 将数据从otherdomain.com发送到mydomain.com

I'm using JSONP to send data from otherdomain.com to mydomain.com

但是，当我尝试在django控制器中解析JSONP数据(views.py)时，我会犯错.

However, I got errer when I tried to parse JSONP data in django controller (views.py).

这是我的代码.

mydomain.com客户端页面中的Javascript

Javascript in mydomain.com client page

jsonData = {
    'foo': 'bar',
}

$.ajax({
    url: 'http://otherdomain.com/end_point/',
    type: 'GET',
    contentType: 'application/json; charset=utf-8',
    data: jsonData,
    dataType : 'jsonp',
    jsonp : 'callback'
});

---

mydomain.com

from django.http import JsonResponse
import json

def decode_jsonp(request):

    if 'callback' in request.GET:
        json_object = json.loads(request.body) # Raise error
        json_object = json.dumps(request.body) # Do not raise error but returns nothing
        json_object = json.loads(json.dumps(request.body)) # Raise error

        foo = json_object['foo']

    return JsonResponse({'foo': foo})

我不知道应该用什么代替json_object = json.loads(request.body)

I don't know what should I substitue for json_object = json.loads(request.body)

推荐答案

JSONP对象在其周围带有括号和一个回调.但是Python的json模块无法识别JSONP对象.因此，您必须首先通过删除周围的括号和回调名称将其转换为JSON对象.

A JSONP object has parentheses around it and a callback. But Python's json module doesn't recognise a JSONP object. So, you'll have to first convert it to JSON object by removing the surrounding parentheses and the callback name.

示例

>>> data = 'callback({"key": "val"})' # a common JSONP object
>>>
>>> json.loads(data)
# raises ValueError
>>>
>>> data_json = data.split("(", 1)[1].strip(")") # convert to json
>>> data_json
'{"key": "val"}'
>>>
>>> json.loads(data_json)
# success

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