groupby和聚合后的Python Pandas排序

问题描述

我试图在对数据(熊猫)进行分组和汇总后进行排序，但我陷入了困境.我的数据:

I am trying to sort data (Pandas) after grouping and aggregating and I am stuck. My data:

data = {'from_year': [2010, 2011, 2012, 2011, 2012, 2010, 2011, 2012],
    'name': ['John', 'John1', 'John', 'John', 'John4', 'John', 'John1', 'John6'],
    'out_days': [11, 8, 10, 15, 11, 6, 10, 4]}
persons = pd.DataFrame(data, columns=["from_year", "name", "out_days"])

days_off_yearly = persons.groupby(["from_year", "name"]).agg({"out_days": [np.sum]})

print(days_off_yearly)

之后，我对数据进行了排序:

After that I have my data sorted:

                out_days
                     sum
from_year name
2010      John        17
2011      John        15
          John1       18
2012      John        10
          John4       11
          John6        4

我想按from_year和out_days的总和对数据进行排序，并希望数据为:

I want to sort my data by from_year and out_days sum and expecting data to be:

                out_days
                     sum
from_year name
2012      John4       11
          John        10
          John6        4
2011      John1       18
          John        15
2010      John        17

我正在尝试

print(days_off_yearly.sort_values(["from_year", ("out_days", "sum")], ascending=False).head(10))

但是得到KeyError:'from_year'.

But getting KeyError: 'from_year'.

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推荐答案

您可以使用 sort_values ，但首先是reset_index，然后是set_index:

You can use sort_values, but first reset_index and then set_index:

#simplier aggregation
days_off_yearly = persons.groupby(["from_year", "name"])['out_days'].sum()
print(days_off_yearly)
from_year  name
2010       John     17
2011       John     15
           John1    18
2012       John     10
           John4    11
           John6     4
Name: out_days, dtype: int64

print (days_off_yearly.reset_index()
                      .sort_values(['from_year','out_days'],ascending=False)
                      .set_index(['from_year','name']))
                 out_days
from_year name
2012      John4        11
          John         10
          John6         4
2011      John1        18
          John         15
2010      John         17

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