本文介绍了bash使用xmllint提取xml属性值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在从xml文件中提取属性值,但是出现错误.我想在 firstpart 元素中提取 key ="qua"
的值.这是我的脚本,但是在下面您会发现错误:
I am extracting an attribute value from xml file, but I get an error.I'd like to extract the value for key="qua"
in the firstpart element. Here is my script, but below you find the errors:
#!/bin/bash
myfile=$1
myvar=$(echo 'cat //firstpart/step/category/id/info[@key="qua"]/@value' | xmllint --xpath "$myfile" | awk -F'[="]' '!/>/{print $(NF-1)}')
echo "$myvar"
我的xml文件的样子:
how my xml file looks like:
<?xml version='1.0' encoding='UTF-8'?>
<firstpart>
<step name="Home">
<category name="one">
<id name="tools">
<info key="qua" value="1"/>
</id>
</category>
</step>
<step name="Contact">
<category name="two">
<id name="tools">
<info key="qua" value="2"/>
</id>
</category>
</step>
...
</firstpart>
<secondpart>
<step name="office">
<category name="one">
<id name="tools">
<info key="qua" value="100"/>
</id>
</category>
</step>
<step name="Contact">
<category name="two">
<id name="tools">
<info key="qua" value="200"/>
</id>
</category>
</step>
...
</secondpart>
我得到的错误:
awk: run time error: negative field index $-1
FILENAME="-" FNR=71 NR=71
./mybash.sh: line 3: $: command not found
./mybash.sh: line 4: $: command not found
推荐答案
似乎您以错误的方式调用了 xmllint
.
It looks like you call xmllint
in wrong way.
xmllint --xpath '//firstpart/step/category/id/info[@key="qua"]/@value' FILE.xml
结果:
value="1" value="2"
完整脚本:
#!/bin/bash
str=$(xmllint --xpath '//firstpart/step/category/id/info[@key="qua"]/@value' $1)
entries=($(echo ${str}))
for entry in "${entries[@]}"; do
result=$(echo $entry | awk -F'[="]' '!/>/{print $(NF-1)}')
echo "result: $result"
done
也许是,这不是更好的解决方案,但至少它可以工作:)
May be, it's not better solution, but at least it works :)
这篇关于bash使用xmllint提取xml属性值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!