我可以通过代码，而不是属性指定XMLRoot？

问题描述

有没有一种方法来设置运行时一个对象或类的xmlroot？

Is there a way to set the xmlroot of an object or class during runtime?

[XmlRoot("data")]
public class MyRoot {
    [XmlElement("bar")]
    public List<RemoteHost> Hosts {get;set;}
}

我没有修改的选项类MyRoot在这种情况下;所以，我想指定我想我之前序列化对象使用XmlSerializer的XML被称为数据根名称。

I don't have the option of modifying the class MyRoot in this case; so, I would like to specify that I want the root name to be called "data" before I serialize the object to XML using XmlSerializer.

推荐答案

是的！简单地说：

var serializer = new XmlSerializer(typeof(MyRoot),
    new XmlRootAttribute("data"));

或者更完全，请参阅 XmlAttributeOverrides 。然而，无论是这些您必须缓存和重用序列化的实例，否则你会泄漏组件。

Or more completely, see XmlAttributeOverrides. However, with either of these you must cache and reuse the serializer instance, otherwise you'll leak assemblies.

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