问题描述
在C ++ 11中，我将如何编写一个函数（或方法），该函数采用已知类型但未知大小的std ::数组？
In C++11, how would I go about writing a function (or method) that takes a std::array of known type but unknown size?
// made up example
void mulArray(std::array<int, ?>& arr, const int multiplier) {
for(auto& e : arr) {
e *= multiplier;
}
}
// lets imagine these being full of numbers
std::array<int, 17> arr1;
std::array<int, 6> arr2;
std::array<int, 95> arr3;
mulArray(arr1, 3);
mulArray(arr2, 5);
mulArray(arr3, 2);
在我的搜索过程中，我只找到使用模板的建议，但是那些看起来很乱（标题中的方法定义）
During my search I only found suggestions to use templates, but those seems messy (method definitions in header) and excessive for what I'm trying to accomplish.
有没有简单的方法来使这个工作，就像一个简单的C风格的数组？
Is there a simple way to make this work, as one would with plain C-style arrays?
推荐答案
否。你真的不能这样做，除非你使你的函数模板（或使用另一种类型的容器，如 std :: vector 在
No. You really cannot do that unless you make your function a function template (or use another sort of container, like an std::vector, as suggested in the comments to the question):
template<std::size_t SIZE>
void mulArray(std::array<int, SIZE>& arr, const int multiplier) {
for(auto& e : arr) {
e *= multiplier;
}
}
这里是。
这篇关于将未知大小的std ::数组传递给函数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！