将动态二维数组从 C++ 传递到 Fortran 并返回

问题描述

在 C++ 和 Fortran 之间传递一个固定的 2D 数组可以正常工作，但我编写的将 2D 动态数组从 C++ 传递到 Fortran 的程序则不然.

Passing a fixed 2D array between C++ and Fortran works fine, however not so with the program I have written to pass a 2D dynamic array from C++ to Fortran.

C++ 端

extern "C" {void array2d_(double **, int *, int *); }
using namespace std;
int main()
{
double **array;
int nx=3;
int ny=2;
int i,j;
cout << "Passing dynamic array from C to Fortran
";
array = (double **) malloc(nx * sizeof(double *));
if(array == NULL)
        {
        fprintf(stderr, "out of memory
");
        exit;
        }
for(i = 0; i < nx; i++)
        {
        array[i] = (double *) malloc(ny * sizeof(double));
        if(array[i] == NULL)
            {
            fprintf(stderr, "out of memory
");
            exit;
            }
        }
for(i = 0; i < nx; i++)
            {
            for(j = 0; j < ny; j++)
                {
                array[i][j]=i+j+i*(2+j)+4;  //random initialisation
                cout << "array[" << i << "][" << j << "]=" << array[i][j] << " ";
                }
            cout << endl;
            }

array2d_(array, &nx, &ny);

for(i = 0; i < nx; i++)
        free(array[i]);
    free(array);
return 0;
}

fortran 方面

subroutine array2d(arr,nx_C,ny_C) bind(C,name="array2d_")
use  iso_c_binding
implicit none
integer (C_INT), intent(IN) :: nx_C,ny_C          !array sizes from C
real (C_DOUBLE), intent(INOUT) :: arr(ny_C,nx_C)
integer :: k,l
print *, "This is in Fortran routine..."
do k = 1,ny_C
do l=1,nx_C
 print *, "arr(",k,",",l,") = ", arr(k,l)
end do
end do
end subroutine array2d

C++ 中的输出是

 array[0][0]=4 array[0][1]=5
 array[1][0]=7 array[1][1]=9
 array[2][0]=10 array[2][1]=13

在 Fortran 中，输出是

While in Fortran the output is

 arr(           1 ,           1 ) =    1.7994937190948764E-305
 arr(           1 ,           2 ) =    7.1027035167764720E-251
 arr(           1 ,           3 ) =    9.8813129168249309E-324
 arr(           2 ,           1 ) =    5.4809152658772852E-317
 arr(           2 ,           2 ) =    1.5475240269406953E-314
 arr(           2 ,           3 ) =    0.0000000000000000

所以不知何故这些值没有正确传递.

So somehow the values are not passed correctly.

推荐答案

主要原因是你的 C 数组是一个锯齿状数组，它是一个指向分隔一维数组的指针数组，而在 Fortran 中，你将参数声明为一个连续的二维数组.两个部分必须使用相同的，最好在 C 中也使用连续数组.

The main reason is that your C array is a jagged array, it is an array of pointers to separate 1D arrays while in Fortran you declare ther argument to be a contiguous 2D array. You must use the same in both parts, preferably use a contiguous array in C too.

只需 malloc 一个大的 nx*ny 缓冲区并将指针设置为行而不是分配它们.您可以在 https://stackoverflow.com/a/5901671/721644

Just malloc one big nx*ny buffer and set the pointers to the rows instead of alloacating them. You can see an example in https://stackoverflow.com/a/5901671/721644

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