问题描述
我有2个表,分别是问题表和答案表结构是这样的:
I have 2 table, that is a question_table and answer_tablethe structure is like this :
我有一个像这样使用php从question_table和answer_table获得的JSON数组.
And I have a JSON array that I got from question_table and answer_table using php like this.
// to get the question
$pertanyaan = "select * from question_table";
$resultPertanyaan = mysqli_query($con, $pertanyaan);
while($rowQuery= mysqli_fetch_array($resultPertanyaan)){
$array_question[]=
array('id'=>$rowQuery['id’],’question’=>$rowQuery['question']);
}
结果是这样的
array_question :
[
{
"id": "8",
"question": "Shop sign/billboard "
},
{
"id": "10",
"question": "Pylon"
},
{
"id": "11",
"question": "Banner"
},
{
"id": "12",
"question": "Sport"
},
{
"id": "14",
"question": "Matic "
},
{
"id": "16",
"question": "Cub"
}
]
获得答案
$jawaban = "select * from answer_table";
$resultJawaban = mysqli_query($con, $jawaban);
while($rowQuery= mysqli_fetch_array($resultJawaban)){
$array_answer[]=
array('id'=>$rowQuery['id'],'remark'=>$rowQuery['remark'],'item'=>$rowQuery['item']);
}
以及类似的结果
array_answer :
[
{
"id": "1b9fa84e-0f2f-11e9-b673-005056be36b2",
"answer": "3",
"id_question": "16"
},
{
"id": "bc82c3fd-0f2e-11e9-b673-005056be36b2",
"answer": "1",
"id_question": "11"
},
{
"id": "cc9363f1-0f2e-11e9-b673-005056be36b2",
"answer": "3",
"id_question": "12"
},
{
"id": "f1dfa8b5-0f2e-11e9-b673-005056be36b2",
"answer": "1",
"id_question": "14"
}
]
我想将array_answer与array_question结合起来,结果如下:
I want to combine array_answer with array_question, which results like this:
array_result :
[
{
"id": "8",
"question": "Shop sign/billboard ",
"asnwer" : null
},
{
"id": "10",
"question": "Pylon",
"asnwer" : null
},
{
"id": "11",
"question": "Banner",
"asnwer" : "1"
},
{
"id": "12",
"question": "Sport",
"answer" : "3"
},
{
"id": "14",
"question": "Matic ",
"answer" : "1"
},
{
"id": "16",
"question": "Cub",
"answer" : "3"
}
]
如何获得预期的array_result?请帮助我,谢谢
How do I get array_result like I expected? Please help me, Thank you
推荐答案
您可以使用array_map
处理每个问题,并在$array_answer
中为每个问题寻找答案:
You can use array_map
to process each of the questions, looking for an answer in $array_answer
for each one:
$questions = json_decode($array_question);
$answers = json_decode($array_answer, true);
$array_result = array_map(function ($v) use ($answers) {
$v->answer = ($k = array_search($v->id, array_column($answers, 'id_question'))) !== false ? $answers[$k]['answer'] : null;
return $v;
}, $questions);
print_r(json_encode($array_result, JSON_UNESCAPED_SLASHES));
输出:
[{"id":"8","question":"Shop sign/billboard ","answer":null},
{"id":"10","question":"Pylon","answer":null},
{"id":"11","question":"Banner","answer":"1"},
{"id":"12","question":"Sport","answer":"3"},
{"id":"14","question":"Matic ","answer":"1"},
{"id":"16","question":"Cub","answer":"3"}
]
更新
对于5.4之前的PHP版本,上述代码存在两个问题.首先,直到5.5.0版之前,array_column
才在PHP中实现.其次,直到PHP 5.4.0才实现JSON_UNESCAPED_SLASHES
常量和相关功能.我们可以使用以下代码来模拟这些代码:
For versions of PHP prior to 5.4, there are a couple of issues with the above code. Firstly array_column
was not implemented in PHP until version 5.5.0. Secondly the JSON_UNESCAPED_SLASHES
constant and associated functionality wasn't implemented until PHP 5.4.0. We can emulate those with this code:
function my_array_column($array, $column) {
return array_map(function ($v) use ($column) { return $v[$column]; }, $array);
}
$array_result = array_map(function ($v) use ($answers) {
$v->answer = ($k = array_search($v->id, my_array_column($answers, 'id_question'))) !== false ? $answers[$k]['answer'] : null;
return $v;
}, $questions);
echo str_replace('\/', '/', json_encode($array_result));
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