问题描述
我正在努力扩展我的熊猫技能。我有一个像这样的pandas数据框：
I am trying to expand my pandas skills. I have a pandas dataframe that looks like this :
df
Group 1 Group 2 Product ID
0 Products International X11
1 Products International X11
2 Products Domestic X11
3 Products Domestic X23
4 Services Professional X23
5 Services Professional X23
6 Services Analytics X25
我正在尝试使用一些pandas功能来获取索引所在的值第1组和第2组更改。我知道我可能不得不逐列，并将这些索引附加到不同的列表中。
I am trying to use some pandas functionality to get the index where the values of Group 1 and Group 2 change. I understand that I will probably have to go column by column, and append these indices into different lists.
我引用了这个问题，这是我能找到的最接近的类似问题。
I have referenced this question Find index where elements change value pandas dataframe which was the closest similar question that I can find.
我想得到这样的输出：
Group 1 changes = [0,4]
Group 2 changes = [0,2,4,6]
如果列中的两个值相同，pandas有哪些内置功能可以快速引用，然后获取该索引？
Is there any sort of built in functionality that pandas has that can quickly reference if two values in a column are the same, and then grab that index?
我的所有数据都按组排序，因此如果解决方案确实涉及逐行迭代，则不应遇到任何问题。
All of my data is sorted by group, so shouldn't run into any problems if the solution does involve iterating row by row.
非常感谢任何帮助！
推荐答案
使用
In [91]: df.ne(df.shift()).apply(lambda x: x.index[x].tolist())
Out[91]:
Group 1 [0, 4]
Group 2 [0, 2, 4, 6]
Product ID [0, 3, 6]
dtype: object
In [92]: df.ne(df.shift()).filter(like='Group').apply(lambda x: x.index[x].tolist())
Out[92]:
Group 1 [0, 4]
Group 2 [0, 2, 4, 6]
dtype: object
同样适用于dict，
In [107]: {k: s.index[s].tolist() for k, s in df.ne(df.shift()).filter(like='Group').items()}
Out[107]: {'Group 1': [0L, 4L], 'Group 2': [0L, 2L, 4L, 6L]}
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