金字塔和FormAlchem​​y管理界面

问题描述

我必须使用formalchem​​y管理界面金字塔项目。我加了基本ACL认证和pyramid_formalchem​​y插件总是丹尼斯即使我验证。

如何只允许经过身份验证的用户使用pyramid_formalchem​​y管理界面有什么想法？

授权政策被添加像这样：

authn_policy = AuthTktAuthenticationPolicy（'MYhiddenSECRET'，回调= groupfinder）
authz_policy = ACLAuthorizationPolicy（）配置=配置（
   设置=设置，
   root_factory ='package.auth.RootFactory'，
   authentication_policy = authn_policy，
   authorization_policy = authz_policy
）＃pyramid_formalchem​​y的配置
config.include（'pyramid_formalchem​​y'）
config.include（'fa.jquery'）
config.formalchem​​y_admin（'管理'，包='包'，查看='fa.jquery.pyramid.ModelView'）

解决方案

pyramid_formalchem​​y 使用权限查看，编辑，删除'，'新'来决定谁可以做什么。在 __ __ ACL 从您的SQLAlchem​​y的模型对象传播下去。因此，你需要把 __ __ ACL 每个允许所需的群体获得这些权限模型对象。例如，从 pyramid_formalchem​​y pyramidapp 示例项目：

  Bar类（基础）：
    __tablename__ ='吧'
    __acl__ = [
            （允许，'管理'，ALL_PERMISSIONS）
            （允许，'bar_manager，（观看，新，编辑，删除））
        ]
    ID =列（整数，primary_key =真）
    富=栏（统一code（255））
 

当然，如果你直到它击中工厂 __ ACL __ 然后它会看在资源树的血统/ code>。默认情况下， pyramid_formalchem​​y 定义了自己的工厂 pyramid_formalchem​​y.resources.Models ，但是你也可以继承这一点，并提供了一​​个 __ __ ACL 将其作为一个全球性的所有车型：

 从pyramid_formalchem​​y.resources进口车型类ModelsWithACL（型号）：
    一个工厂来覆盖默认安全设置
    __acl__ = [
            （允许，'管理'，ALL_PERMISSIONS）
            （允许，认证，观看），
            （允许，'编辑'，'编辑'），
            （允许，'经理'，（'新'，'编辑'，'删除'））
        ]config.formalchem​​y_admin（'管理'，包='包'，查看= ... =工厂ModelsWithACL）
 

I have a pyramid project using the formalchemy admin interface. I added the basic ACL authentication and the pyramid_formalchemy plugin always denys even though I am authenticated.

Any thoughts on how only allow authenticated users to use the pyramid_formalchemy admin interface?

The authorization policy was add like this:

authn_policy = AuthTktAuthenticationPolicy('MYhiddenSECRET', callback=groupfinder)
authz_policy = ACLAuthorizationPolicy()

config = Configurator(
   settings=settings,
   root_factory='package.auth.RootFactory',
   authentication_policy=authn_policy,
   authorization_policy=authz_policy
)

# pyramid_formalchemy's configuration
config.include('pyramid_formalchemy')
config.include('fa.jquery')
config.formalchemy_admin('admin', package='package', view='fa.jquery.pyramid.ModelView')

解决方案

pyramid_formalchemy uses the permissions 'view', 'edit', 'delete', 'new' to determine who can do what. The __acl__ is propagated down from your SQLAlchemy model object. Thus, you need to put an __acl__ on each of your model objects allowing your desired groups access to those permissions. For example, from the pyramid_formalchemy pyramidapp example project:

class Bar(Base):
    __tablename__ = 'bar'
    __acl__ = [
            (Allow, 'admin', ALL_PERMISSIONS),
            (Allow, 'bar_manager', ('view', 'new', 'edit', 'delete')),
        ]
    id = Column(Integer, primary_key=True)
    foo = Column(Unicode(255))

Of course, if you do not supply an __acl__ then it will look in the lineage of the resource tree until it hits the factory. By default, pyramid_formalchemy defines its own factory pyramid_formalchemy.resources.Models, however you can subclass this and provide an __acl__ to it, as a global for all of your models:

from pyramid_formalchemy.resources import Models

class ModelsWithACL(Models):
    """A factory to override the default security setting"""
    __acl__ = [
            (Allow, 'admin', ALL_PERMISSIONS),
            (Allow, Authenticated, 'view'),
            (Allow, 'editor', 'edit'),
            (Allow, 'manager', ('new', 'edit', 'delete')),
        ]

config.formalchemy_admin('admin', package='package', view=..., factory=ModelsWithACL)

这篇关于金字塔和FormAlchem​​y管理界面的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！