NumPy数组的最小-最大归一化

问题描述

我有以下numpy数组:

I have the following numpy array:

foo = np.array([[0.0, 10.0], [0.13216, 12.11837], [0.25379, 42.05027], [0.30874, 13.11784]])

产生:

[[  0.       10.     ]
 [  0.13216  12.11837]
 [  0.25379  42.05027]
 [  0.30874  13.11784]]

如何标准化此数组的Y分量.所以它给了我类似的东西:

How can I normalize the Y component of this array. So it gives me something like:

[[  0.       0.   ]
 [  0.13216  0.06 ]
 [  0.25379  1    ]
 [  0.30874  0.097]]

推荐答案

请参阅此交叉验证链接，，看来您可以在foo的最后一列执行最小-最大标准化.

Referring to this Cross Validated Link, How to normalize data to 0-1 range?, it looks like you can perform min-max normalisation on the last column of foo.

v = foo[:, 1]   # foo[:, -1] for the last column
foo[:, 1] = (v - v.min()) / (v.max() - v.min())

foo

array([[ 0.        ,  0.        ],
       [ 0.13216   ,  0.06609523],
       [ 0.25379   ,  1.        ],
       [ 0.30874   ,  0.09727968]])

---

执行归一化的另一种方法(由OP建议)是使用sklearn.preprocessing.normalize，其产生的结果略有不同-

---

Another option for performing normalisation (as suggested by OP) is using sklearn.preprocessing.normalize, which yields slightly different results -

from sklearn.preprocessing import normalize
foo[:, [-1]] = normalize(foo[:, -1, None], norm='max', axis=0)

foo

array([[ 0.        ,  0.2378106 ],
       [ 0.13216   ,  0.28818769],
       [ 0.25379   ,  1.        ],
       [ 0.30874   ,  0.31195614]])

这篇关于NumPy数组的最小-最大归一化的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！