本文介绍了重命名列表项的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有以下列表listaValores

listaValores <- c()
  for(valores in 1:numRepeticion){
    listaValores <- c(listaValores, readWorksheetFromFile(file = file.read,
                        sheet = sheet.read,
                        startRow = startRow.read+(12*(valores-1)),
                        startCol = startCol.read[i],
                        endRow = startRow.read+((12*valores)-1) ,
                        endCol = startCol.read[i], header = FALSE))
    }

返回:

$Col1
 [1] 32824 35646 34650 29328 27376 28548 35363 34740 49181 57960 55550 50626

$Col1
 [1] 52610 55085 58576 51300 50968 58104 56585 38273 54216 59043 67487 58067

$Col1
 [1] 59142 68593 77510 73434 83545 83483 79635 69269 85703 73080

如何将其元素重命名为201420152016?

How to renames it's elements to 2014, 2015, 2016?

推荐答案

请注意,您有list.因此,您没有colnames,而是names.您可以像这样编辑它们:

Note that you have a list. Therefore, you do not have colnames but names. You can edit them like this:

l <- list(col1 = c(123123, 12123, 123123), col1 =  c(123123, 12123, 123123))
l
# $col1
# [1] 123123  12123 123123
#
# $col1
# [1] 123123  12123 123123

names(l)
# [1] "col1" "col1"

names(l) <- c("2014", "2015")

l

# $`2014`
# [1] 123123  12123 123123
#
# $`2015`
# [1] 123123  12123 123123

要仅编辑列表中的某些条目,请指定索引:

To only edit certain entries in the list, specify an index:

names(l)[1] <- "new_name"

l

# $`new_name`
# [1] 123123  12123 123123
#
# $`2015`
# [1] 123123  12123 123123

如果您想进一步了解R中的不同数据类型,我可以推荐哈德利·威克姆(Hadley Wickham)的摘要.

If you'd like to know more about the different data types in R, I can recommend Hadley Wickham's summary.

这篇关于重命名列表项的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-11 13:31