问题描述
使用可变参数模板,尝试看看可以做什么,我发现自己想知道一些事情:(已经,有点奇怪,但是与我一起)
Playing a bit with variadic templates to try and see what could be done with them, I found myself wondering about something: (granted, it's a bit weird, but bare with me)
让我们假设我有一个类可以接受其他几个类作为模板参数,每个类都有一个嵌套类(我们称之为nested_class):
Let's suppose I have a class which can take several other classes as template parameters, each of them have a nested class (let's call it nested_class):
template<typename... Classes> class MyClass {
class InnerClass { ... };
};
我想实现的是在MyClass内部,创建一个继承自每个参数类的类嵌套类。
what I would like to achieve is inside MyClass, create a class that inherits from each of the parameters classes nested class.
例如:
class A1 {
public:
struct nested_class {
do_stuff() { ... }
};
};
class A2 {
public:
struct nested_class {
do_other_stuff() { ... }
};
};
using C = MyClass<A1, A2>;
这个想法是C有它的嵌套类InnerClass继承A1 :: nested_class和A2 :: nested_class。
the idea would be that C has it's nested class InnerClass that inherits A1::nested_class and A2::nested_class.
有没有什么可以实现这样的事情?我个人不能找出一种方法,但也许这是可能的。
将继承层次结构构建器,如Alexandrescu的层次结构生成器(可在Loki中找到:)会有什么帮助吗?
Would there be anything that could achieve such a thing? I personally can't figure out a way, but maybe it is possible.Would inheritance hierarchy builders like Alexandrescu's Hierarchy Generators (which can be found in Loki: http://loki-lib.sourceforge.net/html/a00653.html) would be of any help?
事先感谢任何人有一个想法。
thanks in advance if anyone has an idea.
推荐答案
使 InnerClass
> nested_class es,你应该使用 Classes :: nested_class ...
模式:
To make InnerClass
derived from all nested_class
es, you should use Classes::nested_class...
pattern:
#include <iostream>
#include <type_traits>
template <class... Classes>
class Myclass
{
public:
class InnerClass: public Classes::nested_class...
{
};
};
class A1 {
public:
struct nested_class {
void do_stuff() { /*...*/ }
};
};
class A2 {
public:
struct nested_class {
void do_other_stuff() { /*...*/ }
};
};
int main()
{
using Class = Myclass<A1, A2>;
std::cout << std::is_base_of<A1::nested_class, Class::InnerClass>::value << std::endl;
std::cout << std::is_base_of<A2::nested_class, Class::InnerClass>::value << std::endl;
return 0;
}
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