问题描述
我有一个场景,我从我的地图服务器获得了许多图块(例如12)。现在对于缓冲和离线功能,我需要再次将它们连接起来,这样我们就必须处理1个单个图像对象而不是12个。我试过没有JAI,我的代码在下面。
I have a scenario in which i`m getting a number of tiles (e.g.12) from my mapping server. Now for buffering and offline functions I need to join them all back again so that we have to deal with 1 single image object instead of 12. I ve tried to do it without JAI my code is below.
package imagemerge;
import java.awt.*;
import java.awt.image.*;
import java.awt.event.*;
public class ImageSticher extends WindowAdapter {
Image tile1;
Image tile2;
Image result;
ColorModel colorModel;
int width,height,widthr,heightr;
//int t1,t2;
int t12[];
public ImageSticher()
{
}
public ImageSticher (Image img1,Image img2,int w,int h)
{
tile1=img1;
tile2=img2;
width=w;
height=h;
colorModel=ColorModel.getRGBdefault();
}
public Image horizontalStich() throws Exception
{
widthr=width*2;
heightr=height;
t12=new int[widthr * heightr];
int t1[]=new int[width*height];
PixelGrabber p1 =new PixelGrabber(tile1, 0, 0, width, height, t1, 0, width);
p1.grabPixels();
int t2[]=new int[width*height];
PixelGrabber p2 =new PixelGrabber(tile2, 0, 0, width, height, t1, 0, width);
p2.grabPixels();
int y, x, rp, rpi;
int red1, red2, redr;
int green1, green2, greenr;
int blue1, blue2, bluer;
int alpha1, alpha2, alphar;
for(y=0;y<heightr;y++)
{
for(x=0;x<widthr;x++)
{
//System.out.println(x);
rpi=y*widthr+x; // index of resulting pixel;
rp=0; //initializing resulting pixel
System.out.println(rpi);
if(x<(widthr/2)) // x is less than width , copy first tile
{
//System.out.println("tile1="+x);
blue1 = t1[rpi] & 0x00ff; // ERROR occurs here
green1=(t1[rpi] >> 8) & 0x00ff;
red1=(t1[rpi] >> 16) & 0x00ff;
alpha1 = (t1[rpi] >> 24) & 0x00ff;
redr = (int)(red1 * 1.0); // copying red band pixel into redresult,,,,1.0 is the alpha valye
redr = (redr < 0)?(0):((redr>255)?(255):(redr));
greenr = (int)(green1 * 1.0); //
redr = (int)(red1 * 1.0); //
greenr = (greenr < 0)?(0):((greenr>255)?(255):(greenr));
bluer = (int)(blue1 * 1.0);
bluer = (bluer < 0)?(0):((bluer>255)?(255):(bluer));
alphar = 255;
//resulting pixel computed
rp = (((((alphar << 8) + (redr & 0x0ff)) << 8) + (greenr & 0x0ff)) << 8) + (bluer & 0x0ff);
}
else // index is ahead of half way...copy second tile
{
blue2 = t2[rpi] & 0x00ff; // blue band bit of first tile
green2=(t2[rpi] >> 8) & 0x00ff;
red2=(t2[rpi] >> 16) & 0x00ff;
alpha2 = (t2[rpi] >> 24) & 0x00ff;
redr = (int)(red2 * 1.0); // copying red band pixel into redresult,,,,1.0 is the alpha valye
redr = (redr < 0)?(0):((redr>255)?(255):(redr));
greenr = (int)(green2 * 1.0); //
redr = (int)(red2 * 1.0); //
greenr = (greenr < 0)?(0):((greenr>255)?(255):(greenr));
bluer = (int)(blue2 * 1.0);
bluer = (bluer < 0)?(0):((bluer>255)?(255):(bluer));
alphar = 255;
//resulting pixel computed
rp = (((((alphar << 8) + (redr & 0x0ff)) << 8) + (greenr & 0x0ff)) << 8) + (bluer & 0x0ff);
}
t12[rpi] = rp; // copying resulting pixel in the result int array which will be converted to image
}
}
MemoryImageSource mis;
if (t12!=null) {
mis = new MemoryImageSource(widthr, heightr, colorModel, t12, 0, widthr);
result = Toolkit.getDefaultToolkit().createImage(mis);
return result;
}
return null;
}
}
现在检查我的理论我 m试图加入或者stich两个tile视频但我
m得到错误:
now to check the my theory Im trying to join or stich two tiles horizontaly but i
m getting the error :
java.lang.ArrayIndexOutOfBoundsException:90000
at imagemerge.ImageSticher.horizontalStich(ImageSticher.java:69)
at imageStream.ImageStream.getImage(ImageStream .java:75)
at imageStream.ImageStream.main(ImageStream.java:28)
java.lang.ArrayIndexOutOfBoundsException: 90000 at imagemerge.ImageSticher.horizontalStich(ImageSticher.java:69) at imageStream.ImageStream.getImage(ImageStream.java:75) at imageStream.ImageStream.main(ImageStream.java:28)
是否有某种限制因为当stiching两个300的图像x 300水平意味着结果图像将是600 x 300 ...这将使180000索引大小,但它在90000给出错误,我在这里做错了什么
is there some kind of limitation because when stiching two images of 300 x 300 horizontally it means the resulting image will be 600 x 300 ... that would make 180000 index size but its giving error at 90000, what am I doing wrong here
推荐答案
rpi
是结果像素的索引,而不是 t1中源图块数据中的索引
,这是一半大小。
rpi
is the index of your resulting pixel, not the index in your source tile data in t1
, which is half the size.
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