本文介绍了如何使用Django 1.6中的HTTP POST请求接收json数据?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在学习 1.6。

我想发布一些使用HTTP POST请求,我正在使用Django进行此任务的学习。

我试图使用请求.POST ['data'] request.raw_post_data request.body 但没有正在为我工​​作。

我的views.py是

I am learning Django 1.6.
I want to post some JSON using HTTP POST request and I am using Django for this task for learning.
I tried to use request.POST['data'], request.raw_post_data, request.body but none are working for me.
my views.py is

import json
from django.http import StreamingHttpResponse
def main_page(request):
    if request.method=='POST':
            received_json_data=json.loads(request.POST['data'])
            #received_json_data=json.loads(request.body)
            return StreamingHttpResponse('it was post request: '+str(received_json_data))
    return StreamingHttpResponse('it was GET request')

我使用 modu乐。

I am posting JSON data using requests module.

import requests
import json
url = "http://localhost:8000"
data = {'data':[{'key1':'val1'}, {'key2':'val2'}]}
headers = {'content-type': 'application/json'}
r=requests.post(url, data=json.dumps(data), headers=headers)
r.text

r.text 应该打印该消息并发布数据,但是我无法解决这个简单的问题。请告诉我如何在Django 1.6中收集发布的数据?

r.text should print that message and posted data but I am not able to solve this simple problem. please tell me how to collect posted data in Django 1.6?

推荐答案

这里您可能会混淆表单编码和JSON数据。 request.POST ['foo'] 用于表单编码数据。您正在发布原始的JSON,因此您应该使用 request.body

You're confusing form-encoded and JSON data here. request.POST['foo'] is for form-encoded data. You are posting raw JSON, so you should use request.body.

received_json_data=json.loads(request.body)

这篇关于如何使用Django 1.6中的HTTP POST请求接收json数据?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-11 12:35