结果从广播接收器返回

结果从广播接收器返回

本文介绍了结果从广播接收器返回的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在从应用程序A向应用程序B发送广泛广播,应用程序B具有BroadCastReceiver来处理意图.

I am sending a broadCast from App A to app B, app B has a BroadCastReceiver to handle intent.

现在,我在App B的BroadcastReceiveronReceive中进行了一些操作,然后我想将结果返回给App A,这样我就可以进行回调,并在结果为正数时继续操作.

Now I do some operation in onReceive in App B's BroadcastReceiver and then I want to get result back to App A, so that I can have a callback, and continue operations if result is positive.

在一些代码下面.

在应用B内部:

public class TripBackupReceiver extends BroadcastReceiver {
@Override
    public void onReceive(Context arg0, Intent arg1) {
        System.out.println("broadcast Received");

        // send result back to Caller Activity
    }
}

内部应用A:

Intent intent = new Intent("a_specified_action_string");
sendBroadcast(intent);

有人可以解决这个问题吗,请向我提出一些建议.谢谢!

Can anybody have any solution for this problem, please guide me with some suggestions. Thanks!!

推荐答案

我正在寻找类似的东西. 极大地帮助了我.

I was looking for something similar. This helped me tremendously.

基本上,代替使用sendBroadcast(Intent),请尝试使用合适的sendOrderedBroadcast()形式,该形式允许设置BroadcastReceiver来处理Receiver的结果.一个简单的例子:

Basically, instead of a sendBroadcast(Intent) try using a suitable form of sendOrderedBroadcast() which allows setting a BroadcastReceiver to handle results form a Receiver. A simple example:

sendOrderedBroadcast(intent, null, new BroadcastReceiver() {
        @SuppressLint("NewApi")
        @Override
        public void onReceive(Context context, Intent intent) {
            Bundle results = getResultExtras(true);

            String trail = results.getString("breadcrumb");
            results.putString("breadcrumb", trail + "->" + "sometext");
            Log.i(TAG, "Final Result Receiver = " + results.getString("breadcrumb", "nil"));
        }
    }, null, Activity.RESULT_OK, null, null);

这篇关于结果从广播接收器返回的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-11 12:35