如何使用＆QUOT;分享图像使用＆QUOT;分享意图在android的共享图像？

问题描述

我在该应用程序，我把所有的图像转换成可提拉 - 华电国际文件夹中的图像厨房的应用程序。我所谓的图像在我的活动是这样的：

 私人整数[] imageIDs = {
        R.drawable.wall1，R.drawable.wall2，
        R.drawable.wall3，R.drawable.wall4，
        R.drawable.wall5，R.drawable.wall6，
        R.drawable.wall7，R.drawable.wall8，
        R.drawable.wall9，R.drawable.wall10
};
 

所以，现在我想知道如何使用共享意向我的推杆共享code这样我分享这个图片：

 按钮shareButton =（按钮）findViewById（R.id.share_button）;
     shareButton.setOnClickListener（新View.OnClickListener（）{
     公共无效的onClick（视图v）{

        意图sharingIntent =新的意图（Intent.ACTION_SEND）;
        乌里screenshotUri = Uri.parse（Images.Media.EXTERNAL_CONTENT_URI +/+ imageIDs）;

        sharingIntent.setType（为image / jpeg）;
        sharingIntent.putExtra（Intent.EXTRA_STREAM，screenshotUri）;
        startActivity（Intent.createChooser（sharingIntent，分享图像使用））;

         }
    }）;
 

和我有分享按钮还当我点击共享按钮共享盒打开但是，当我cliked任何服务主要是它的崩溃或者一些服务说：无法打开图片所以，我怎么能解决这个问题，或有任何othere格式code共享图像????

编辑：

我试着用下面的code。但它不工作。

 按钮shareButton =（按钮）findViewById（R.id.share_button）;
     shareButton.setOnClickListener（新View.OnClickListener（）{
     公共无效的onClick（视图v）{

        意图sharingIntent =新的意图（Intent.ACTION_SEND）;
        乌里screenshotUri = Uri.parse（android.resource：//com.android.test/*）;
        尝试 {
            InputStream的流= getContentResolver（）openInputStream（screenshotUri）。
        }赶上（FileNotFoundException异常E）{
            // TODO自动生成的catch块
            e.printStackTrace（）;
        }
        sharingIntent.setType（为image / jpeg）;
        sharingIntent.putExtra（Intent.EXTRA_STREAM，screenshotUri）;
        startActivity（Intent.createChooser（sharingIntent，分享图像使用））;

         }
    }）;
 

如果不介意有人PLZ纠正我的上述code或给我一个适当的例子PLZ如何从绘制，华电国际文件夹

分享我的图片

解决方案

 位图图标= mBitmap;
意图份额=新的意图（Intent.ACTION_SEND）;
share.setType（为image / jpeg）;
ByteArrayOutputStream字节=新ByteArrayOutputStream（）;
icon.com preSS（Bitmap.Com pressFormat.JPEG，100个字节）;
文件F =新的文件（Environment.getExternalStorageDirectory（）+文件分割符+temporary_file.jpg）;
尝试 {
    f.createNewFile（）;
    FileOutputStream中FO =新的FileOutputStream（F）;
    fo.write（bytes.toByteArray（））;
}赶上（IOException异常E）{
        e.printStackTrace（）;
}
share.putExtra（Intent.EXTRA_STREAM，Uri.parse（文件：///sdcard/temporary_file.jpg））;
startActivity（Intent.createChooser（份额，共享图片））;
 

I have image galley app in that app I placed all the images into the drawable-hdpi folder.and i called images in my activity like this :

private Integer[] imageIDs = {
        R.drawable.wall1, R.drawable.wall2,
        R.drawable.wall3, R.drawable.wall4,
        R.drawable.wall5, R.drawable.wall6,
        R.drawable.wall7, R.drawable.wall8,
        R.drawable.wall9, R.drawable.wall10
};

So now i want know how do i share this images using sharing Intent i putted sharing code like this :

     Button shareButton = (Button) findViewById(R.id.share_button);
     shareButton.setOnClickListener(new View.OnClickListener() {
     public void onClick(View v) {

        Intent sharingIntent = new Intent(Intent.ACTION_SEND);
        Uri screenshotUri = Uri.parse(Images.Media.EXTERNAL_CONTENT_URI + "/" + imageIDs);

        sharingIntent.setType("image/jpeg");
        sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri);
        startActivity(Intent.createChooser(sharingIntent, "Share image using"));

         }
    });

And i have sharing button also when i click on share button Sharing box is openingBut when i cliked any service mostly its crashing or some services say : unable to open imageSo how i can fix this or is there any othere format code to share images ????

Edit :

I tried using the code below. But its not working.

Button shareButton = (Button) findViewById(R.id.share_button);
     shareButton.setOnClickListener(new View.OnClickListener() {
     public void onClick(View v) {

        Intent sharingIntent = new Intent(Intent.ACTION_SEND);
        Uri screenshotUri = Uri.parse("android.resource://com.android.test/*");
        try {
            InputStream stream = getContentResolver().openInputStream(screenshotUri);
        } catch (FileNotFoundException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        sharingIntent.setType("image/jpeg");
        sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri);
        startActivity(Intent.createChooser(sharingIntent, "Share image using"));

         }
    });

If don't mind somebody plz correct my above code OR give me a proper example plz How do i Share my images from drawable-hdpi folder

解决方案

Bitmap icon = mBitmap;
Intent share = new Intent(Intent.ACTION_SEND);
share.setType("image/jpeg");
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
icon.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
File f = new File(Environment.getExternalStorageDirectory() + File.separator + "temporary_file.jpg");
try {
    f.createNewFile();
    FileOutputStream fo = new FileOutputStream(f);
    fo.write(bytes.toByteArray());
} catch (IOException e) {
        e.printStackTrace();
}
share.putExtra(Intent.EXTRA_STREAM, Uri.parse("file:///sdcard/temporary_file.jpg"));
startActivity(Intent.createChooser(share, "Share Image"));

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