使用INNER JOIN加载模型

本文介绍了使用INNER JOIN加载模型的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

假设我有一个Phalcon\Mvc\Model，我已经使用::findFirst($id)加载了它.

Let's say I have a Phalcon\Mvc\Model that I load using ::findFirst($id).

如何交换将加载模型行并在其他表上进行INNER JOIN的自定义查询?

How can I swap in a custom query that would load the model row and do INNER JOIN on some other table?

谢谢！

推荐答案

我确定您可以将查询"构建器用于简单的联接，例如:

I'm sure you can use the Query builder for simple joins like:

<?php

//Getting a whole set
$robots = $this->modelsManager->createBuilder()
    ->from('Robots')
    ->join('RobotsParts')
    ->orderBy('Robots.name')
    ->getQuery()
    ->execute();

//Getting the first row
$robots = $this->modelsManager->createBuilder()
    ->from('Robots')
    ->join('RobotsParts')
    ->orderBy('Robots.name')
    ->getQuery()
    ->getSingleResult();

或文档中的PHQL示例:

Or PHQL example from the documentation:

<?php

$phql = "SELECT Robots.*
    FROM Robots JOIN RobotsParts p
    ORDER BY Robots.name LIMIT 20";
$result = $manager->executeQuery($phql);

默认情况下，假定为INNER JOIN.不过，您可以在查询中指定JOIN的类型.

By default, an INNER JOIN is assumed. You can specify the type of JOIN in the query though.

参考: http: //docs.phalconphp.com/en/latest/reference/phql.html#creating-queries-using-the-query-builder

然后，我将重载模型的findFirst()方法以利用上述代码并将结果值分配给模型的属性.

Then I'd overload model's findFirst() method to utilize the above code and assign result values to model's properties.

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