在不知道JSON格式的情况下在Java中解析JSON

在不知道JSON格式的情况下在Java中解析JSON

本文介绍了在不知道JSON格式的情况下在Java中解析JSON的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试解析Java中的JSON字符串并找到键值对,以便我可以确定JSON对象的近似结构,因为JSON字符串的对象结构是未知的。

I am trying to parse JSON strings in Java and find the key-value pairs so that I can determine the approximate structure of the JSON object since object structure of JSON string is unknown.

例如,一次执行可能有这样的JSON字符串:

For example, one execution may have a JSON string like this:

  {"id" : 12345, "days" : [ "Monday", "Wednesday" ], "person" : { "firstName" : "David", "lastName" : "Menoyo" } }

还有这样的:

  {"url" : "http://someurl.com", "method" : "POST", "isauth" : false }

我如何循环遍历各种JSON元素并确定键及其值?我看了 jackson-core 的。我知道如何抓住下一个令牌并确定它是什么类型的令牌(即字段名称,值,数组启动等),但是,我不知道如何获取实际令牌的值。

How would I cycle through the various JSON elements and determine the keys and their values? I looked at jackson-core's JsonParser. I see how I can grab the next "token" and determine what type of token it is (i.e., field name, value, array start, etc), but, I don't know how to grab the actual token's value.

例如:

public void parse(String json)  {
  try {
     JsonFactory f = new JsonFactory();
     JsonParser parser = f.createParser(json);
     JsonToken token = parser.nextToken();
     while (token != null) {
        if (token.equals(JsonToken.START_ARRAY)) {
           logger.debug("Start Array : " + token.toString());
        } else if (token.equals(JsonToken.END_ARRAY)) {
           logger.debug("End Array : " + token.toString());
        } else if (token.equals(JsonToken.START_OBJECT)) {
           logger.debug("Start Object : " + token.toString());
        } else if (token.equals(JsonToken.END_OBJECT)) {
           logger.debug("End Object : " + token.toString());
        } else if (token.equals(JsonToken.FIELD_NAME)) {
           logger.debug("Field Name : " + token.toString());
        } else if (token.equals(JsonToken.VALUE_FALSE)) {
           logger.debug("Value False : " + token.toString());
        } else if (token.equals(JsonToken.VALUE_NULL)) {
           logger.debug("Value Null : " + token.toString());
        } else if (token.equals(JsonToken.VALUE_NUMBER_FLOAT)) {
           logger.debug("Value Number Float : " + token.toString());
        } else if (token.equals(JsonToken.VALUE_NUMBER_INT)) {
          logger.debug("Value Number Int : " + token.toString());
        } else if (token.equals(JsonToken.VALUE_STRING)) {
           logger.debug("Value String : " + token.toString());
        } else if (token.equals(JsonToken.VALUE_TRUE)) {
           logger.debug("Value True : " + token.toString());
        } else {
           logger.debug("Something else : " + token.toString());
        }
        token = parser.nextToken();
     }
  } catch (Exception e) {
     logger.error("", e);
  }
}

中是否有类jackson 或生成树的其他库( gson simple-json ),或允许一个循环遍历json元素并获取除值之外的实际键名?

Is there a class in jackson or some other library (gson or simple-json) that produces a tree, or allows one to cycle through the json elements and obtain the actual key names in addition to the values?

推荐答案

看一看。

你的代码将是:

public void parse(String json)  {
       JsonFactory factory = new JsonFactory();

       ObjectMapper mapper = new ObjectMapper(factory);
       JsonNode rootNode = mapper.readTree(json);

       Iterator<Map.Entry<String,JsonNode>> fieldsIterator = rootNode.fields();
       while (fieldsIterator.hasNext()) {

           Map.Entry<String,JsonNode> field = fieldsIterator.next();
           System.out.println("Key: " + field.getKey() + "\tValue:" + field.getValue());
       }
}

这篇关于在不知道JSON格式的情况下在Java中解析JSON的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-11 09:28