问题描述
我为我的数据表编写了一个如下代码,这些代码填充表中的内容,如下所示:
if (datatable!= null)
datatable.destroy();
datatable = $('#tableProducts')。DataTable({
pageLength:50,
bLengthChange:false,
processing:true ,
serverSide:true,
filter:true,
orderMulti:false,
bSort:false,
ajax:{
url:/ Bulk / LoadData /,
type:POST,
data:{
username:$(。sellerInput ).val(),
drange:$(。select2)。val()
},
成功:函数(数据){
}
$ b数据:ImageURL,
name:
Title,
render:function(data,type,row){
return'< td>< img src ='+ data +'>< / td>';
},
autoWidth:true
},
{
data:Sales,
name:QuantitySold,
render:function(data,type,row){
return'< td>'+ data +'< / td>'
},
$ b $ data $ currentPrice
name name:CurrenctPrice
render:function(data,type,row){
return'< td> < b> $'+ data +'< / b>< / td>'
},
}
]
});
如果我没有指定成功回调,这个工作很好。如果我指定成功回调像这样(也在上面的代码中显示):
ajax:{
url:/ Bulk / LoadData /,
type:POST,
data:{
username:$(。sellerInput)。val ),
drange:$(。select2)。val()
},
成功:函数(数据){
//一些自定义代码和+用数据库填充数据表...
}
},
这里的问题是,如果我指定成功回调,然后更新我的HTML页面的其他部分,那么数据表不会加载DB中的数据。
我的问题是,如果我重写数据表的成功回调函数,以便更新我的HTML页面的更多部分,只显示数据表本身,我该如何手动指定数据表的数据源?
有人能帮我吗?
success
来获取响应数据 试试这个:
ajax:{
url:/ Bulk / LoadData /,
type:POST,
data:function(d){
d .username:$(。sellerInput).val(),
d.drange:$(。select2).val()
},
dataSrc:function数据){
//一些自定义代码在这里,并用我的数据库中的数据填充数据表...
console.log(data);
返回数据;
}
},
注意:另外你试图发送额外的参数为 username
和 drange
,所以在DataTable中我们应该使用 data:function(d){
as function to send extra param
I have written a following code for my datatables which fills up the table with contents from my DB like this:
if (datatable != null)
datatable.destroy();
datatable = $('#tableProducts').DataTable({
"pageLength": 50,
"bLengthChange": false,
"processing": true,
"serverSide": true,
"filter": true,
"orderMulti": false,
"bSort": false,
"ajax": {
"url": "/Bulk/LoadData/",
"type": "POST",
"data": {
"username": $(".sellerInput").val(),
"drange": $(".select2").val()
},
success: function (data) {
}
},
"columns": [
{
"targets": -1,
"data": "ImageURL",
"name": "Title",
"render": function (data, type, row) {
return '<td><img src=' + data + '></td>';
},
"autoWidth": true
},
{
"data": "Sales",
"name": "QuantitySold",
"render": function (data, type, row) {
return '<td>' + data + '</td>'
},
},
{
"data": "CurrentPrice",
"name": "CurrenctPrice",
"render": function (data, type, row) {
return '<td> <b>$ ' + data + '</b></td>'
},
}
]
});
And this works just fine if I don't specify the success callback. If I specify the success callback like this ( also shown in code above):
"ajax": {
"url": "/Bulk/LoadData/",
"type": "POST",
"data": {
"username": $(".sellerInput").val(),
"drange": $(".select2").val()
},
success: function (data) {
// some custom code here and + filling up datatable with data from my DB...
}
},
The problem here is if I specify the success callback and then update other parts of my HTML page, then the datatable doesn't loads up the data in DB..
My question is, how can I manually specify the data source for datatable if I override the datatable's success callback function in order to update more parts of my HTML page insteade of just the datatable itself?
Can someone help me out ?
You can use dataSrc
instead of success
to get the response data
Try this:
"ajax": {
"url": "/Bulk/LoadData/",
"type": "POST",
"data": function (d){
d.username: $(".sellerInput").val(),
d.drange: $(".select2").val()
},
"dataSrc": function (data) {
// some custom code here and + filling up datatable with data from my DB...
console.log(data);
return data;
}
},
Note: Also you are trying to send extra param's as username
and drange
, so in DataTable we should use "data":function(d){
as function to send extra param
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