问题描述
以下代码如何将此数组按数字顺序排序？
How does the following code sort this array to be in numerical order?
var array=[25, 8, 7, 41]
array.sort(function(a,b){
return a - b
})
我知道如果计算结果是......
I know that if the result of the computation is...
小于0 ：a被排序为比b更低的索引。
零：a和b被视为相等，并且不执行排序。
大于0 ：b被排序为比a更低的索引。
Less than 0: "a" is sorted to be a lower index than "b".
Zero: "a" and "b" are considered equal, and no sorting is performed.
Greater than 0: "b" is sorted to be a lower index than "a".
数组排序回调函数是否在多次调用期间被调用排序的过程？
Is the array sort callback function called many times during the course of the sort?
如果是这样，我想知道每次将哪两个数字传递给函数。我假设它首先取25（a）和8（b），然后是7（a）和41（b），所以：
If so, I'd like to know which two numbers are passed into the function each time. I assumed it first took "25"(a) and "8"(b), followed by "7"(a) and "41"(b), so:
25（a） - 8（b）= 17（大于零，所以将b排序为比a更低的索引）：8,25
25(a) - 8(b) = 17 (greater than zero, so sort "b" to be a lower index than "a"): 8, 25
7（a） - 41（b）= -34（小于零，所以将a排序为比b更低的索引：7,41
7(a) - 41(b) = -34 (less than zero, so sort "a" to be a lower index than "b": 7, 41
这两组数字如何相互排序？
How are the two sets of numbers then sorted in relation to one another?
请帮助一个苦苦挣扎的新手！
Please help a struggling newbie!
推荐答案
是
你可以找到你的自己：
array.sort((a,b) => {
console.log(`comparing ${a},${b}`);
return a > b ? 1
: a === b ? 0
: -1;
});
编辑
这是我得到的输出：
25,8
25,7
8,7
25,41
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