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问题描述
我想将json的某些字段映射到类的内部字段。例如
I want to map some fields of json to inner fields of a class. e.g
{
values:[{
"name":"Abc",
"age":18,
"street":"test",
"postalcoad":"1231412"
},
{
"name":"ccvb",
"age":20,
"street":"test2",
"postalcoad":"123"
}
]}
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@JsonIgnoreProperties(ignoreUnknown = true)
public class Customer{
@JsonProperty("name")
private string name;
@JsonProperty("age")
private int age;
private Address address;
}
@JsonIgnoreProperties(ignoreUnknown = true)
public class Address{
@JsonProperty("street")
private string street;
@JsonProperty("postalcode")
private string postalcode;
}
ObjectMapper mapper = new ObjectMapper();
Customer[] c = mapper.readValue(mapper.readTree(json).get("values").toString(), Customer[].class);
它返回没有地址的Customer对象。知道如何从这个json创建Address对象。
It returns me Customer object without Address. Any idea how can i create Address object from this json.
推荐答案
其中一个选项是使用 @JsonCreator
注释:
@JsonCreator
public Customer(
@JsonProperty("name") String name,
@JsonProperty("age") int age,
@JsonProperty("street") String street,
@JsonProperty("postalcode") String postalcode
) {
this.name = name;
this.age = age;
this.address = new Address();
this.address.street = street;
this.address.postalcode = postalcode;
}
第二个选项是创建自定义反序列化器并绑定你的使用 @JsonDeserialize
注释使用反序列化程序的类
Second option is create custom deserializer and bind your class with deserializer using @JsonDeserialize
annotation
@JsonDeserialize(using = CustomerDeserializer.class)
public static class Customer{
....
}
public class CustomerDeserializer extends StdDeserializer<Customer> {
public CustomerDeserializer() {
super(Customer.class);
}
@Override
public Customer deserialize(JsonParser p, DeserializationContext ctxt) throws IOException, JsonProcessingException {
Customer customer = new Customer();
JsonNode treeNode = p.readValueAsTree();
if (treeNode == null) {
return null;
}
customer.setName(treeNode.get("name").asText());
customer.setAge(treeNode.get("age").asInt());
Address address = new Address();
address.setStreet(treeNode.get("street").asText());
address.setPostalcode(treeNode.get("postalcode").asText());
customer.setAddress(address);
return customer;
}
}
作为第三选项,您可以使用 @JsonAnySetter
进行某种后期构造处理:
As third option, you can use @JsonAnySetter
with some kind of post construct processing:
public interface PostConstruct {
void postConstruct();
}
public class Customer implements PostConstruct {
//mapping
private Map<String, Object> additionalFields = new HashMap<>();
@JsonAnySetter
public void setAdditionalValue(String key, Object value) {
additionalFields.put(key, value);
}
@Override
public void postConstruct() {
address = new Address();
address.setStreet(String.valueOf(additionalFields.get("street")));
address.setPostalcode(String.valueOf(additionalFields.get("postalcode")));
}
}
public static class PostConstructDeserializer extends DelegatingDeserializer {
private final JsonDeserializer<?> deserializer;
public PostConstructDeserializer(JsonDeserializer<?> deserializer) {
super(deserializer);
this.deserializer = deserializer;
}
@Override
protected JsonDeserializer<?> newDelegatingInstance(JsonDeserializer<?> newDelegatee) {
return deserializer;
}
@Override
public Object deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException {
Object result = _delegatee.deserialize(jp, ctxt);
if (result instanceof PostConstruct) {
((PostConstruct) result).postConstruct();
}
return result;
}
}
//using of post construct deserializer
ObjectMapper mapper = new ObjectMapper();
SimpleModule module = new SimpleModule();
module.setDeserializerModifier(new BeanDeserializerModifier() {
@Override
public JsonDeserializer<?> modifyDeserializer(DeserializationConfig config,
BeanDescription beanDesc,
final JsonDeserializer<?> deserializer) {
return new PostConstructDeserializer(deserializer);
}
});
mapper.registerModule(module);
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